Classical bonding in NaH2PO4

Chemistry

1 answer:

lesantik [10]2 years ago

7 0

$NaH_2PO_4$ , a crystal structure with a short symmetrical hydrogen bond.

<h3>What is Classical bonding?</h3>

Classical models of the chemical bond. By classical, we mean models that do not take into account the quantum behaviour of small particles, notably the electron. These models generally assume that electrons and ions behave as point charges which attract and repel according to the laws of electrostatics.

Sodium dihydrogen phosphate is a derivative composed of glycerol derivatives formed by reacting mono and diglycerides that are derived from edible sources with phosphorus pentoxide followed by neutralization with sodium carbonate.

Bonding in $NaH_2PO_4$

$NaH_2PO_4$ , a crystal structure with a short symmetrical hydrogen bond. Sodium dihydrogen phosphate ( $NaH_2PO_4$ ) is monoclinic, space group P2,/c, with a= 6.808 (2), b= 13.491 (3), c=7.331 (2)/~, fl=92.88 (3) ; Z=8.

Learn more about the bond here:

brainly.com/question/10777799

#SPJ1

You might be interested in

Rank the effective nuclear charge Z* experienced by a valence electron in each of these atoms:

LekaFEV [45]

Answer:

The atoms are ranked in decreasing order as follows:

Fluorine ---4

Carbon ----3

Boron ------2

Beryllium --1

Explanation:

Effective nuclear charge (Zeff) is defined as the difference between the actual nuclear charge (the atomic number, Z) and the shielding constant (S).

It is calculated by finding the atomic number and electronic configuration, attributing a shielding value to each electron, adding all the shielding values and using the formula:

Z eff = Z - S

Effective nuclear charges:

An atom of carbon: 3.25

An atom of fluorine: 5.20

An atom of beryllium: 1.95

An atom of boron: 2.60

5 0

3 years ago

The most common source of copper (cu) is the mineral chalcopyrite (cufes2). how many kilograms of chalcopyrite must be mined to

ser-zykov [4K]

The formula of chalcopyrite is CuFeS₂.
The molar mass of chalcopyrite - 183.5 g/mol
The mass of Cu in 1 mol of chalcopyrite is - 63.5 g
When 183.5 g of chalcopyrite is mined, the mass of Cu obtained - 63.5 g
So if 63.g of Cu is needed mass of chalcopyrite required - 183.5 g
Then to gain 370 g of pure Cu - mass of chalcopyrite needed -183.5/63.5 x 370
therefore mass of chalcopyrite to be mined - 1069.21 g

4 0

4 years ago

How are changes in state related to thermal energy and particle motion

frozen [14]

Answer:

search it

Explanation:

6 0

3 years ago

vinegar contains 5.0g of acetic acid, ch3cooh, in 100.0 ml of solution what is the molarity of acetic acid in vinegar

Lana71 [14]

Find number of moles and divide by volume to get molarity