1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kvasek [131]
2 years ago
11

Classical bonding in NaH2PO4

Chemistry
1 answer:
lesantik [10]2 years ago
7 0

NaH_2PO_4, a crystal structure with a short symmetrical hydrogen bond.

<h3>What is Classical bonding?</h3>

Classical models of the chemical bond. By classical, we mean models that do not take into account the quantum behaviour of small particles, notably the electron. These models generally assume that electrons and ions behave as point charges which attract and repel according to the laws of electrostatics.

Sodium dihydrogen phosphate is a derivative composed of glycerol derivatives formed by reacting mono and diglycerides that are derived from edible sources with phosphorus pentoxide followed by neutralization with sodium carbonate.

Bonding in NaH_2PO_4

NaH_2PO_4, a crystal structure with a short symmetrical hydrogen bond. Sodium dihydrogen phosphate (NaH_2PO_4) is monoclinic, space group P2,/c, with a= 6.808 (2), b= 13.491 (3), c=7.331 (2)/~, fl=92.88 (3) ; Z=8.

Learn more about the bond here:

brainly.com/question/10777799

#SPJ1

You might be interested in
How many atoms are equal to 1.5 moles of hellium
ANTONII [103]

Answer:

There are 1.8×1024 atoms in 1.5 mol HCl

Explanation:

6 0
3 years ago
Read 2 more answers
PLEASE HELP ME, 20 POINTS
Marrrta [24]

Explanations:

<u>Question</u> <u>1:</u> Lithium in 20.00+ g is C. or D., but 25.00+ g is D. which means this is the correct option.

I am unsure of <u>Question</u> <u>2</u>. I don't think it is mole though.

<u>Question</u> <u>3:</u> Boron in 25.00-30.00 g is B. or D., but 25.00 g would be C.

<u>Question</u> <u>4:</u> 2.393 x 1024 atoms of Oxygen is 63.58 mole O. I don't know for sure, but I think this is correct.

<u><em>I am NOT professional. There is a chance I am incorrect. Please reply to me if I've made a mistake.</em></u>

4 0
2 years ago
If a gas occupies 1532.7 mL at standard temperature, what volume does it occupy at 49.4 ºC if the pressure remains constant?
ElenaW [278]

Answer:

a. 1810mL

Explanation:

When conditions for a gas change under constant pressure (and the number of molecules doesn't change), it follows Charles' Law:

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}  where the temperatures must be measured in Kelvin

To convert from Celsius to Kelvin, add 273, or use the equation:  T_C+273=T_K

For this problem, one must also recall that standard temperature is 0°C (or 273K).

So, T_1 = 273[K], and T_2 = (49.4+273)[K]=322.4[K].

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

\dfrac{(1532.7[mL])}{(273[K])}=\dfrac{V_2}{(322.4[K])}

\dfrac{(1532.7[mL])}{(273[K\!\!\!\!\!{-}])}(322.4[K\!\!\!\!\!{-}] )=\dfrac{V_2}{(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})

1810.04571428[mL]=V_2

Adjusting for significant figures, this gives V_2=1810[mL]

4 0
2 years ago
A 6.1-kg solid sphere, made of metal whose density is 2600 kg/m3, is suspended by a cord. When the sphere is immersed in a liqui
deff fn [24]

Answer:

Density of the liquid = 1470.43 kg/m³

Explanation:

Given:

Mass of solid sphere(m) = 6.1 kg

Density of the metal = 2600 kg/m³

Thus volume of the liquid :

Volume(V)=\frac{Mass(m)}{Density (\rho)}

Volume of the sphere = 6.1 kg/2600 kg/m³ = 0.002346 m³

The volume of water displaced is equal to the volume of sphere (Archimedes' principle)

Volume displaced = 0.002346 m³

Buoyant force =\rho\times gV

Where

\rho is the density of the fluid

g is the acceleration due to gravity

V is the volume displaced

The free body diagram of the sphere is shown in image.

According to image:

mg=\rho\times gV+T

Acceleration due to gravity = 9.81 ms⁻²

Tension force = 26 N

Applying in the equation to find the density of the liquid as:

6.1\times 9.81=\rho\times 9.81\times 0.002346+26

33.841=\rho\times 9.81\times 0.002346

\rho=\frac{33.841}{9.81\times 0.002346}

\rho=1470.43 kgm^3

<u>Thus, the density of the liquid = 1470.43 kg/m³</u>

6 0
3 years ago
What are the spectator ions in the equation below? Select all that apply.
Licemer1 [7]

Answer:

H+ and NO3- ions

Explanation:

The Pb²+ ions react with the SO4²‐ ions to form a solid precipitate, i.e. they bond together and undergo a phase change;

On the contrary, the H+ and NO3- ions are aqueous ions before the reaction and the same after the reaction, i.e. they don't change;

Hence, the H+ and NO3- ions are spectator ions

The way to do this type of question is to consider what changes and what doesn't, look at phase changes and oxidation state changes

7 0
3 years ago
Other questions:
  • Which of the dollowing isotopes have 8 neutrons in the nucleus?<br> 0-15<br> 0-17<br> C13<br> O C14
    12·2 answers
  • Naturally occurring solid mixture of one or more minerals and organic matter
    11·1 answer
  • 1.00 L of a gas at STP is compressed to 473mL. What is the new pressure of gas?
    9·1 answer
  • A 45.9 g sample of a metal is heated to 95.2°c and then placed in a calorimeter containing 120.0 g of water (c = 4.18 j/g°c) at
    9·1 answer
  • Which of the following is fact-based science rather than part of a belief system
    13·2 answers
  • Who else like this????!?!?!?!?!
    15·1 answer
  • How are elements labeled on the periodic table that have the same number of<br> valence electrons?
    10·1 answer
  • How many grams are in .997 moles of N205?
    9·1 answer
  • Which of the following statements is true?
    10·1 answer
  • Does the coating from another type of candy dissolve in water like M&amp;M’s ?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!