The answer is (2) higher vapor pressure and weaker intermolecular forces. Propanone has a lower boiling point, so it is more volatile than water. Propanone's vapor pressure is, therefore, higher than that of water at 50 degrees Celsius. Propanone is more volatile due to the fact that the intermolecular forces that hold its molecuels together are not as strong as those that hold together molecules of water. Since the IMFs are weaker, it takes less thermal energy to break individual molecules free of each other.
A cone of depression occurs in an aquifer when groundwater is pumped from a well. In an unconfined aquifer, this is an actual depression of the water levels. In confined aquifers, the cone of depression is a reduction in the pressure head surrounding the pumped well.
The answer for the following question is answered below.
- <em><u>Therefore the new pressure of the gas is 1.76 atm.</u></em>
Explanation:
Given:
Initial pressure of the gas = 1.34 atm
Initial temperature of the gas = 273 K
final temperature of the gas = 312 K
To solve:
Final temperature of the gas
We know;
From the ideal gas equation
P × V = n × R × T
So;
from the above equation we can say that
<em>P ∝ T</em>
= constant
= 
Where;
= initial pressure of a gas
= final pressure of a gas
= initial temperature of a gas
= final temperature of a gas
= 
= 1.76 atm
<em><u>Therefore the new pressure of the gas is 1.76 atm.</u></em>
Wouldn't it be just dubble the amount witch would be 300.0g water
Answer:
C nhé ! CH3COOH là axit chứ không phải este
