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anyanavicka [17]
3 years ago
11

Groups are an important method of classifying because

Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
4 0
<h3>Answer:</h3>

                Option-D, "their elements have very similar properties and exhibit a clear trend" is the correct answer.

<h3>Explanation:</h3>

                         In periodic table the elements are arranged in tabular form with respect to their atomic masses, atomic numbers, electronic configurations and chemical properties. It is called periodic because the properties of elements repeats periodically.

                         Furthermore, the rows from left to right also called Periods basically shows the metallic and non metallic characters of elements. \those on the left are metals and those at the rights are non metals.

                        The columns from top to bottom are called as Groups. Groups contain elements of same chemical properties.

<h3>Example:</h3>

Group I elements are called as <em>Alkali Metals</em>. They all have one valence electron and hence, loose one electron to form the corresponding cation. i.e.

                                           M    →    M⁺¹  +  1 e⁻

Group VII elements are called <em>Halogens</em>, they all are non metals and tend to gain one electron to form the corresponding halide ion. i.e.

                                           X  +  1 e⁻    →    X⁻¹

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I need yall help with this one and i can make yall brilientist if u get it right plus yall get 50 points
mixas84 [53]

Answer:

D

Explanation:

6 0
2 years ago
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6. Identify the number of neutrons in one atom of silicon with an isotopic mass number of 28 amu.
Sholpan [36]

14

Explanation:

The number of neutrons in one atom of silicon with an isotopic mass number of 28amu is 14.

An atom is made up three fundamental sub-atomic particles which are:

  Protons, neutron and electrons

Protons are the positively charged particles in an atom

Neutrons do not carry any charges

Electrons are the negatively charged particles.

In the nucleus of an atom, both protons and neutrons can be found. They are the massive particle in an atom.

  The mass number of an atom = number of protons + number of neutrons

Number of neutrons = mass number - number of protons.

From the periodic table, we know that silicon has an atomic number of 14.

The atomic number is the number of protons in an atom:

         Number of neutrons = 28 - 14 = 14amu

In the atom, we will have 14amu of neutrons in a silicon atom.

learn more:

Number of neutrons brainly.com/question/2757829

#learnwithBrainly

5 0
3 years ago
How are mutations different? Provide examples.
Murljashka [212]

Answer:

sdoawjdiowadawoi siokdwajsiokwjDIWIAdawidjaskmdnkawdjad kadakwdkawdawhdaw

Explanation: im smart

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3 years ago
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I need help with this! I WILL GIVE YOU BRAINLIST!
melisa1 [442]

Answer:

Farther, longer, longer

Explanation:

The further away a planet is from the sun, the larger the orbit. This makes the time for the planet to make a revolution around the sun longer.

8 0
2 years ago
Assume that you have a cylinder with a movable piston. What would happen to the gas pressure inside the cylinder if you do the f
pishuonlain [190]

Answer:

A. The pressure will increase 4 times. P₂ = 4 P₁

B. The pressure will decrease to half its value. P₂ = 0.5 P₁

C. The pressure will decrease to half its value. P₂ = 0.5 P₁

Explanation:

Initially, we have n₁ moles of a gas that occupy a volume V₁ at temperature T₁ and pressure P₁.

<em>What would happen to the gas pressure inside the cylinder if you do the following?</em>

<em />

<em>Part A: Decrease the volume to one-fourth the original volume while holding the temperature constant. Express your answer in terms of the variable P initial.</em>

V₂ = 0.25 V₁. According to Boyle's law,

P₁ . V₁ = P₂ . V₂

P₁ . V₁ = P₂ . 0.25 V₁

P₁ = P₂ . 0.25

P₂ = 4 P₁

<em>Part B: Reduce the Kelvin temperature to half its original value while holding the volume constant. Express your answer in terms of the variable P initial.</em>

T₂ = 0.5 T₁. According to Gay-Lussac's law,

\frac{P_{1}}{T_{1}} =\frac{P_{2}}{T_{2}}\\\frac{P_{1}}{T_{1}} =\frac{P_{2}}{0.5T_{1}}\\\\P_{2}=0.5P_{1}

<em>Part C: Reduce the amount of gas to half while keeping the volume and temperature constant. Express your answer in terms of the variable P initial.</em>

n₂ = 0.5 n₁.

P₁ in terms of the ideal gas equation is:

P_{1}=\frac{n_{1}.R.T_{1}}{V_{1}}

P₂ in terms of the ideal gas equation is:

P_{2}=\frac{n_{2}.R.T_{1}}{V_{1}}=\frac{0.5n_{1}.R.T_{1}}{V_{1}}=0.5P_{1}

3 0
3 years ago
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