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Neporo4naja [7]
3 years ago
14

A triangle has the following side lengths: x - 2, x, and 3x + 1. Another triangle has the following side lengths: 2x - 5, x + 4,

6x - 7. If the perimeters of the two triangles are equal, what is x?
Mathematics
1 answer:
Leto [7]3 years ago
6 0

Since we know that the perimeters are equal, we can make an equation where the sum of the side lengths of one triangle equal the sum of the side lengths of the other triangle. This yields (x-2)+(x)+(3x+1)=(2x-5)+(x+4)+(6x-7). If we combine like turns, the equation becomes 5x-1=9x-8. We can use the subtraction property of equality to isolate the x and the integers by saying 9x-5x=-1-(-8). Simplifying this gives 4x=7 or x=1.75

Hope this helps.

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First day:

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Total: $194

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7 0
2 years ago
What is the value of x in the inequality start fraction seven minus two x over negative four end fraction plus two less than neg
algol13

Answer:

x

Step-by-step explanation:

\frac{7-2x}{-4} +2

Subtract 2 from both sides

\frac{7-2x}{-4}

mutliply both sides by -4, flip the inequality

7-2x >4x+8

Add 2x on both sideds

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Subtract 8 from both sides

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3 0
3 years ago
What are the steps for using integer tiles to evaluate the expression 45 divided by 15
Goryan [66]
The answer is B. Hope you get it.
6 0
3 years ago
Read 2 more answers
Find out for what value of the variable:
Burka [1]

Answer:

a=-1,\ a=-5

x=-2+i,\ -2-i

Step-by-step explanation:

<u>Equations</u>

We have two cases where some variable is required to be found such that some condition is met. The first case is about finding the value of a that complies:

a^2+7a+6=a+1

Rearranging

a^2+6a+5=0

Factoring:

(a+1)(a+5)=0

There are two solutions:

a=-1,\ a=-5

The second case requires us to find the value of x such that

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Rearranging

x^2+4x+5=0

This second-degree equation has no real roots. We'll offer the imaginary (complex) solutions:

x=-2+i,\ -2-i

5 0
3 years ago
A^-5b^-4/a^-13b^8 a. a^8 b^12 b. ab^5 c. a^8/b^12 d.b^-9/b^-5
lord [1]
If you would like to solve a^(-5)b^(-4) / a^(-13)b^8,  you can do this using the following steps:

a^(-5)b^(-4) / a^(-13)b^8 = a^13 / a^5b^4b^8 = a^8 / b^12

The correct result would be c. a^8 / b^12.
5 0
3 years ago
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