Question

The length of a rectangle is six times its width.

Answer 1

Alright, so we'll be playing a little with variables around here. The question tells you the length of a rectangle is six times its width, or that l=6w. 

The perimeter of a rectangle is 2l + 2w (two times the length + two times the width). Since we established that l=6w...

2(6w) + 2w = 98 yd
12w + 2w = 98 yd
14w=98 yd
w=7 yd. 

But it doesn't stop there. We found that the width is 7 yd. So the length is 6w, or 6 x 7 yd, which is 42 yd. To find the area of a rectangle, you multiply the length by the width. 

So...42 yd x 7 yd = 294 yd^2. 

Hope that helped.