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Wewaii [24]
4 years ago
7

A rectangle hale card has a length of 3/10 and a width of 4/5 find the perimeter

Mathematics
1 answer:
postnew [5]4 years ago
4 0

Answer:

22/10 or 2 and 1/5

Step-by-step explanation:

To find the perimeter, add all sides together. Since it's a rectangle, the other sides are the same measurement as the ones given. Add 3/10, 3/10, 4/5, and 4/5 together. To do this, find a common denominator. The lowest common denominator is 10 so multiply the 4/5 by 2/2 to get the denominator to be 10. Now, add 3/10, 3/10, 8/10, and 8/10. It adds up to 22/10 but if you don't want an improper fraction, simplify it to 2 and 1/5.

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A street is drawn by dilating segment FG¯ about center A with a scale factor greater than 0 but less than 1. Is this an enlargem
Arte-miy333 [17]

Answer: This is an reduction.

Step-by-step explanation:

  • A dilation a king of transformation that creates an similar image (about a center of dilation) of the actual figure by changing its size with the use of a scale factor(k).
  • It either shrinks or stretches the image.
  1. If |k| is greater than 1 then the image is an enlargement .
  2. If |k| is less than 1 then the image is an reduction.
  3. If |k| is equals to 1 then there is no change in size.

Given : A street is drawn by dilating segment \overline{FG} about center A with a scale factor greater than 0 but less than 1.

Then by using (2.) , we can say that this is an reduction.

5 0
3 years ago
Solve for x. −6>−30−4x−6>−30-4x enter the inequality in the first box.
Bogdan [553]
If you would like to solve -6 > -30 - 4x for x, you can do this using the following steps:

-6 > -30 - 4x
4x > -30 + 6
4x > -24      /4
x > -24/4
x > -6

The correct result would be x > -6.
5 0
3 years ago
Read 2 more answers
Select the smallest fraction from the following fractions.<br> 2/4<br> 3/6<br> 1/3 <br> 7/9
enot [183]

Answer:

it 1/3

Step-by-step explanation:

2/4 is just 1/2, 3/6 is also 1/2, 7/9 is over 1/2 and 1/3 is the only one less then 1/2 so it's the lowest fraction. This is not the proper way to solve it but it works and it's faster

3 0
3 years ago
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Tommy has 6 more than 3 times the amount of money in his bank account than Judy. Judy has $7500 more than a number in her accoun
Ad libitum [116K]

Answer:

Amount of money Judy has in her account is \$(7500+n).

Amount of money Tommy has in his account is  \$(22506+3n)

Step-by-step explanation:

To find : Amount of money in Judy account and amount of money in Tommy account:

Solution:

Given:

Judy has $7500 more than a number in her account.

Let the number be 'n'.

So we can say that;

Amount of money in Judy account is equal to 7500 plus number.

framing in equation form we get;

Amount of money in Judy account = \$(7500+n)

Hence Amount of money Judy has in her account is \$(7500+n).

Now Given:

Tommy has 6 more than 3 times the amount of money in his bank account than Judy.

So we can say that;

Amount of money in Tommy account is equal to 3 multiplied by Amount of money in Judy account plus 6.

framing in equation form we get;

Amount of money in Tommy account = 3(7500+n)+6 =22500+3n+6=\$(22506+3n)

Hence Amount of money Tommy has in his account is  \$(22506+3n).

8 0
3 years ago
On a coordinate plane, an image rectangle has points (negative 5, 0), (5, 0), A prime (5, negative 5), (negative 5, negative 5).
aev [14]

Answer:(5/3,5/3)

Step-by-step explanation: I did the test ;D

6 0
3 years ago
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