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3 years ago

When the function f(x) = 6(9)x is changed to f(x) = 6(9)x + 1, what is the effect?

Mathematics

2 answers:

S_A_V [24]3 years ago

7 0

Answer:

The answer would be:

The y-intercept is 1 space higher.

Step-by-step explanation:

i did the test

weeeeeb [17]3 years ago

5 0

The answer would be:
The y-intercept is 1 space higher.

This equation is a y=mx+b and if you didn't already know, the +b is the y-intercept. It's where the equation intersects with the y line. Since the original equation didn't have one, it means it passed through the origin and now that it has one, the intersection would be (0,1). Because of this, the whole equation would shift up 1 whole unit.

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3 years ago

If f(x) = 72(1.25)^x and f(1) = 72(1.25)^1 = 11.25 f(2) = 72(1.25)^2 = ?????????

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The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure

Novosadov [1.4K]

Hello!

The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure?

Use 3.14 to approximate π .

Enter your answer in the box. in.³

Data: (Cylinder)

h (height) = 7 in

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: $\pi \approx 3.14$

V (volume) = ?

Solving: (Cylinder volume)

$V = \pi *r^2*h$

$V = 3.14 *2.5^2*7$

$V = 3.14*6.25*7$

$V = 137.375 \to \boxed{V_{cylinder} \approx 137.38\:in^3}$

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: $\pi \approx 3.14$

If: We know that the volume of a sphere is $V = 4* \pi * \dfrac{r^3}{3}$ , but we have a hemisphere, so the formula will be half the volume of the hemisphere $V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}$