Indeed, the production of a gas is an indication that a new substance was produced as result of the reaction of the matter that constitutes the antiacid tablet and the distilled water.

A chemical reaction is a change that yields the formation of new substances (products), due to the rearrangements of the atoms of the reactants.

In a very simple form, you can represent a chemical reaction by the general equation:

Reactants → Products

Which means that some elements or compounds, those in the reactant side of the equation, undergo a change in which some chemical bonds are broken, the atoms separate from the original substances and combine into a new arrangement in which they form one or more different substances (products).

The option B), that the table dissapeared is not a clear evidence of a chemical change because it could have been dissolved, which is a physical change.

Also, the option C), that there was a color change, cannot be cited as an evidence of a chemical reaction, since the color is a physical property.

As for the option D, that there was a change in mass, is not a viable option, since mass cannot change either with a chemical or physical change.

3 0

3 years ago

Mr. Turner is driving through downtown Houston at 35 MPH (15.56 m/s). This is above the posted speed limit and there are cars pa

monitta

Answer:

Mr. Turner will not be able to stop in time.

a = - 71.2 m/s²

s₁ = 11.67 m

Explanation:

Since, Mr. Turner is driving at 45.56 m/s and his reaction time for applying brakes is 3/4th of a second. So, the distance covered by car in this time will be:

s₁ = vt

where,

s₁ = distance covered by car before applying brakes = ?

v = speed of car = 15.56 m/s

t = reaction time = 3/4th of second = 0.75 s

Therefore,

s₁ = (15.56 m/s)(0.75 s)

s₁ = 11.67 m

and the distance required for the car to stop after applying brakes is:

s₂ = 1.7 m

So, the total distance traveled by car before stopping will be:

s = s₁ + s₂

s = 11.67 m 1.7 m

s = 13.37 m

since, the driver was 13.3 m ahead.

Therefore, Mr. Turner will not be able to stop in time.

To find the deceleration of Mr. Turner after applying brakes we use 3rd equation of motion:

2as₂ = Vf² - Vi²

where,

a = deceleration = ?

Vf = Final Velocity = 0 m/s

Vi = Initial velocity = 15.56 m/s

Therefore,

2a(1.7 m) = (0 m/s)² - (15.56 m/s)²

a = - (242.1136 m²/s²)/3.4 m

a = - 71.2 m/s²

5 0

3 years ago