The answer is B because you are not using force or energy as if you were if you were to lift or push something.
Greater or more acceleration
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Answer:
- <u><em>Option A) A gas was produced.</em></u>
Explanation:
Indeed, the production of a gas is an indication that a new substance was produced as result of the reaction of the matter that constitutes the antiacid tablet and the distilled water.
A chemical reaction is a change that yields the formation of new substances (products), due to the rearrangements of the atoms of the reactants.
In a very simple form, you can represent a chemical reaction by the general equation:
Which means that some elements or compounds, those in the reactant side of the equation, undergo a change in which some chemical bonds are broken, the atoms separate from the original substances and combine into a new arrangement in which they form one or more different substances (products).
The option B), that the table dissapeared is not a clear evidence of a chemical change because it could have been dissolved, which is a physical change.
Also, the option C), that there was a color change, cannot be cited as an evidence of a chemical reaction, since the color is a physical property.
As for the option D, that there was a change in mass, is not a viable option, since mass cannot change either with a chemical or physical change.
Answer:
Mr. Turner will not be able to stop in time.
a = - 71.2 m/s²
s₁ = 11.67 m
Explanation:
Since, Mr. Turner is driving at 45.56 m/s and his reaction time for applying brakes is 3/4th of a second. So, the distance covered by car in this time will be:
s₁ = vt
where,
s₁ = distance covered by car before applying brakes = ?
v = speed of car = 15.56 m/s
t = reaction time = 3/4th of second = 0.75 s
Therefore,
s₁ = (15.56 m/s)(0.75 s)
<u>s₁ = 11.67 m</u>
and the distance required for the car to stop after applying brakes is:
s₂ = 1.7 m
So, the total distance traveled by car before stopping will be:
s = s₁ + s₂
s = 11.67 m 1.7 m
s = 13.37 m
since, the driver was 13.3 m ahead.
<u>Therefore, Mr. Turner will not be able to stop in time.</u>
To find the deceleration of Mr. Turner after applying brakes we use 3rd equation of motion:
2as₂ = Vf² - Vi²
where,
a = deceleration = ?
Vf = Final Velocity = 0 m/s
Vi = Initial velocity = 15.56 m/s
Therefore,
2a(1.7 m) = (0 m/s)² - (15.56 m/s)²
a = - (242.1136 m²/s²)/3.4 m
<u>a = - 71.2 m/s²</u>