Answer:
1. the electric potential energy of the electron when it is at the midpoint is - 2.9 x
J
2. the electric potential energy of the electron when it is 10.0 cm from the 3.00 nC charge is - 5.04 x
J
Explanation:
given information:
= 3 nC = 3 x
C
= 2 nC = 2 x
C
r = 50 cm = 0.5 m
the electric potential energy of the electron when it is at the midpoint
potential energy of the charge, F
F = k 
where
k = constant (8.99 x
)
electron charge,
= - 1.6 x
C
since it is measured at the midpoint,
r = 
= 0.25 m
thus,
F = 
= k
+ k
=
(
)
= (8.99 x
)( - 1.6 x
)(3 x
+2 x
)/0.25
= - 2.9 x
J
the electric potential energy of the electron when it is 10.0 cm from the 3.00 nC charge
= 10 cm = 0.1 m
= 0.5 - 0.1 = 0.4 m
F = k
+ k
=
(
+
)
= (8.99 x
)( - 1.6 x
)(3 x
/0.1+2 x
/0.4)
= - 5.04 x
J
Answer:
Vf=3
Explanation:
you must first write your data
data before impact
M1=1000 M2=5000
V1=0 m/s V2 =0m/s
data after impact
M1=1000 M2=5000
V1=15m/s V2=?
M1V1 +M2V2=M1V1 +M2V2f
(1000)(0)+(5000)(0)=(1000)(15)+(5000)Vf
0=15000+5000Vf
- 15000÷5000=5000Vf÷5000
Vf= -3
Vf =3
Potential and kinetic energy are the two types of energy, but they do get separated into subgroups, for which I do not know. Hope that helps.
Reading a book in your warm, comfy seat ... in Row-27 of a
passenger airliner cruising at 450 miles per hour.