Answer:
See below.
Step-by-step explanation:
By definition the median of the triangle bisects the base of the isosceles triangle.
We need to prove that the 2 triangles formed by the median are congruent.
If the 2 triangles are ABD and ACD where BD is the median and < ABC is the angle from which BD is drawn.
BD = BD ( the common side)
AD = DC ( because BD is the median).
AB = AC ( because ABC is an isosceles triangle).
So Triangles ABD and ACD are congruent by SSS.
Therefore m < ABD = m < CBD, so BD is the bisector of < ABC.
To prove BD is also the altitude:
Triangles ABD and CBD are congruent as we have just proven. Therefore the
of measure of the base angle ABD = m < CBD . Also they are adjacent angles ( on the same line) so they add up to 180.
Therefore angles ABD and CBD are both right angles and BD is the altitude of triangle ABC.
You start by changing both the a common denominator, this case it would be 100 so it’s 2/100 and 5/100, since 1/50 and 2/100 is the same, each 1/100 is equal to “6” and you have 5/100, which is EQUAL TO 30
Answer:
525267262525226
Step-by-step explanation:
594944+757548484-848484%
Y = mx + b (m = 3) y-intercept (0,4)
y = 3x + 4
hope this helps, God bless!
