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3 years ago

Which layer of the atmosphere reflects radio waves back to Earth? Mesosphere Stratosphere Thermosphere Troposphere BRAINLEST

Mathematics

2 answers:

hodyreva [135]3 years ago

7 0

Answer: Thermosphere

It EZ

nataly862011 [7]3 years ago

6 0

Answer:

ionosphere

Step-by-step explanation:

In radio communication, skywave or skip refers to the propagation of radio waves reflected or refracted back toward Earth from the ionosphere, an electrically charged layer of the upper atmosphere

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A museum worker randomly displays 5 historical writings in a row. What is the probability that the worker lines them up from the

Mars2501 [29]

The number of ways to arrange the 5 writings in a row is 5! = 5 * 4 * 3 * 2 * 1 = 120 ways.

There is only 1 way to arrange the writings from oldest to newest.

Therefore, the probability is 1/120.

4 0

3 years ago

Amy’s cake shop is building a three tier circular wedding cake. The top layer has a radius measuring 2.5 inches. The next layer

Gemiola [76]

It would be 8.5 because all you have to do is add 3 to 2.5 then you’ll get 5.5 then do that one more time.

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2 years ago

13) Please Help With This Question.<br> WILL MARK BRAINLIEST. + 10 POINTS!!!

jeka94

Answer should be B.
second choice

8 0

3 years ago

Read 2 more answers

PLEASE HELP!!! Use addition to solve the linear system of equations. Include all of your work in your final answer. 2x + y = 5,

Arturiano [62]

I: 2x+y=5
II:3x+2y=4

start by eliminating y

-2*I: -4x-2y=-10
II: 3x+2y=4

add both equations together

-2*I+II: -4x-2y+3x+2y=-10+4
-1x=-6
x=6

insert x=6 into I:
2*6+y=5
y=5-12
y=-7

so the solution is x=6, y=-7

4 0

3 years ago

EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att

aliina [53]

$y=x(x-2)^2$
$\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0$
$\implies x=\dfrac23,x=2$

are the critical points, and judging by the picture alone, you must have $b=\dfrac23$ and $a=2$ . (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

$\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43$

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of $\dfrac{\mathrm dy}{\mathrm dx}=y'$ , which entails first finding the second derivative:

$y'=3x^2-8x+4$
$\implies y''=6x-8$

setting equal to 0 and finding the critical point:

$6x-8=0\implies x=\dfrac86=\dfrac43$

This is to say the minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ *occurs when $x=\dfrac43$ *, but this is not necessarily the same as saying that $\dfrac43$ is the actual minimum value.

The minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ is obtained by evaluating the derivative at this critical point:

$m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43$

4 0

3 years ago