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Neporo4naja [7]
3 years ago
14

Find three solutions of the equation. y = –8x

Mathematics
1 answer:
stepladder [879]3 years ago
5 0

Answer:16,24,8

Step-by-step explanation:

1|x=2

y=_8*2

 =_16

2|x=3

y=_8*3

 =_24

3|x=_1

y=_8*_1

 =8

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Mrs pender shows her students 2 sticks measuring 6 inches and 2 sticks measuring 8 inches. She asked the student to arrange the
MrMuchimi

Answer:

The answer is A got it correct on the test

Step-by-step explanation:

have a good day!

3 0
3 years ago
What is √36ab^4c^5 ?
Zanzabum
You'll need to use parentheses to indicate what is under the first radical sign and what is not.  Did you mean radical(36a) or just radical 36?

I will assume that you meant radical(36a).

Then you have [radical(36a}*(b^4)*c^5.

This comes out to 6sqrt(a)*b^4*c^5.
3 0
3 years ago
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KatRina [158]
I am almost positive the answer is B

5 0
3 years ago
Read 2 more answers
You and your friend are standing back-to-back. Your friend runs 16 feet forward and then 12 feet right. At the same time, you ru
Arte-miy333 [17]
Add 16+12 to get 28.
Add 9+12 to get 21.

Think of these as the sides of a triangle.
a^2+b^2=c^2
28^2+21^2=1225
√1225=35

You threw the ball 35 feet.

3 0
4 years ago
Farmers know that driving heavy equipment on wet soil compresses the soil and injures future crops. Here are data on the "penetr
Greeley [361]

Answer:

Step-by-step explanation:

Hello!

To see if driving heavy equipment on wet soil compresses it causing harm to future crops, the penetrability of two types of soil were measured:

Sample 1: Compressed soil

X₁: penetrability of a plot with compressed soil.

n₁= 20 plots

X[bar]₁= 2.90

S₁= 0.14

Sample 2: Intermediate soil

X₂: penetrability of a plot with intermediate soil.

n₂= 20 (with outlier) n₂= 19 plots (without outlier)

X[bar]₂= 3.34 (with outlier) X[bar]₂= 2.29 (without outlier)

S₂= 0.32 (with outlier) S₂= 0.24 (without outlier)

Outlier: 4.26

Assuming all conditions are met and ignoring the outlier in the second sample, you have to construct a 99% CI for the difference between the average penetration in the compressed soil and the intermediate soil. To do so, you have to use a t-statistic for two independent samples:

Parámeter of interest: μ₁-μ₂

Interval:

[(X[bar]₁-X[bar]₂)±t_{n_1+n_2-2;1-\alpha/2}*Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }]

t_{n_1+n_2-2;1-\alpha/2}= t_{20+19-2;1-(0.01/2)}= t_{37; 0.995}= 2.715

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{19*0.0196+18*0.0576}{20+19-2} }= 0.195= 0.20

[(2.90-2.29)±2.715*0.20\sqrt{\frac{1}{20} +\frac{1}{19} }]

[0.436; 0.784]

I hope this helps!

5 0
3 years ago
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