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2 years ago

A company surveyed all of the employees in their Columbus, Ohio office,

Mathematics

1 answer:

satela [25.4K]2 years ago

7 0

Answer:

B. They did not survey employees in other offices around the country

Step-by-step explanation:

1. A random sample is when you randomly choose options from the whole list. In this case, they make it clear that there are other offices. They didn't give a chance to the rest of the offices to take a survey.

2. Surveying "all" the employees is not what a random sample is. A random sample is supposed to help make it more distributed among the people you survey. Making all of them take it in a cluster is not random.

3. The other choices don't make sense because they don't mention anything about them: nothing about the employees working 5 years, nothing about it being conducted electronically, and nothing about a time limit.

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Solve for x in the equation.

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Answer:

The solution is $\displaystyle x=1\pm \sqrt{47}$ . Fourth option

Explanation:

Solve for x:

$2x^2+3x-7=x^2+5x+39$

Move all the terms from the right to the left side of the equation, a zero in the right side:

$2x^2+3x-7-x^2-5x-39=0$

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$x^2-2x-46=0$

The general form of the quadratic equation is:

$ax^2+bx+c=0$

Solve the quadratic equation by using the formula:

$\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

In our equation: a=1, b=-2, c=-46

Substituting into the formula:

$\displaystyle x=\frac{-(-2)\pm \sqrt{(-2)^2-4(1)(-46)}}{2(1)}$

$\displaystyle x=\frac{2\pm \sqrt{4+184}}{2}$

$\displaystyle x=\frac{2\pm \sqrt{188}}{2}$

Since 188=4*47

$\displaystyle x=\frac{2\pm \sqrt{4*47}}{2}$

Take the square root of 4:

$\displaystyle x=\frac{2\pm 2\sqrt{47}}{2}$

Divide by 2:

$\displaystyle x=1\pm \sqrt{47}$

First option: Incorrect. The answer does not match

Second option: Incorrect. The answer does not match

Third option: Incorrect. The answer does not match

Fourth option: Correct. The answer matches exactly this option

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3 years ago

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Answer:

$=49.5cm^3$

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Step-by-step explanation:

$V=whl=2.75*6*3=49.5cm^3$

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3 years ago

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So 5/3 is not an irrational number, it's rational.

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