Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
∠3 = 60°
Step-by-step explanation:
Since g and h are parallel lines then
∠1 and ∠2 are same side interior angles and are supplementary, hence
4x + 36 +3x - 3 = 180
7x + 33 = 180 ( subtract 33 from both sides )
7x = 147 ( divide both sides by 7 )
x = 21
Thus ∠2 = (3 × 21) - 3 = 63 - 3 = 60°
∠ 2 and ∠3 are alternate angles and congruent, hence
∠3 = 60°