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3 years ago

Describe a Sankey Diagram and how it can be used.

Chemistry

1 answer:

jolli1 [7]3 years ago

4 0

Explanation:

Sankey diagrams , which are typically used to visualize energy transfers between processes, are named after the Irishman Matthew H. P. R. Sankey, who used this type of diagram in a publication on energy efficiency of a steam engine in 1898.

Sankey diagrams are ideal for visually representing energy balances.

how to use

1.Overview. The Sankey diagram displays how quantities are distributed among items between two or more stages.

2.Add a Sankey diagram. Choose the Data Visualization or Re-Visualize option from the toolbar and select Sankey Diagram.

3.Change link color and width.

4.Change node color.

5.Change labels and tooltips.

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a sample of gas with a volume of 30.0 ml at 25.0 °c is heated to 50.0 degrees celsius. what is the new volume of the gas?

mart [117]

Answer : The new volume of the gas is, 32.5 mL

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number o moles of gas.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=30.0mL\\T_1=25.0^oC=(25.0+273)K=298K\\V_2=?\\T_2=50.0^oC=(50.0+273)K=323K$

Putting values in above equation, we get:

$\frac{30.0mL}{298K}=\frac{V_2}{323K}\\\\V_2=32.5mL$

Therefore, the new volume of the gas is, 32.5 mL

4 0

3 years ago

A flexible container at an initial volume of 6.13 L contains 6.51 mol of gas. More gas is then added to the container until it r

aivan3 [116]

Answer:

the final mole of the flexible container = 12.92 moles

Explanation:

Given that :

initial volume of a flexible container = 6.13 L

initial mole of a flexible container = 6.51 mol

final volume of a flexible container = 18.3 L

final mole of a flexible container = ???

Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

Therefore,

$n= \dfrac{V_2*n_1}{V_1}$

$n= \dfrac{18.3*6.51}{6.13}$

n = 19.43

$n=n_1+n_2$

19.43 = 6.51 + n₂

n₂ = 19.43 - 6.51

n₂ = 12.92 moles

Thus; the final mole of the flexible container = 12.92 moles

6 0

3 years ago

Part C<br> Number of molecules in 8.437x10-2 mol C6H6

N76 [4]

Answer:

There are $5.08\times 10^{22}\ \text{molecules of}\ C_6H_6$

Explanation:

In this problem, we need to find the number of molecules in $8.437\times 10^{-2}$ mol of $C_6H_6$ .

The molar mass of $C_6H_6$ is $6\times 12+1\times 6=78\ g/mol$

No of moles = mass/molar mass

We can find mass from above formula.

$m=n\times M\\\\m=8.437\times 10^{-2}\ mol\times 78\ g/mol\\\\m=6.58\ g$

Also,

No of moles = no of molecules/Avogadro number

$N=n\times N_A\\\\N=8.437\times 10^{-2}\times 6.023\times 10^{23}\\\\N=5.08\times 10^{22}\ \text{molecules}$

Hence, there are $5.08\times 10^{22}\ \text{molecules of}\ C_6H_6$

5 0

3 years ago

What should you do with a rag that has been used to wipe up spilled gasoline? a)Place it in the bilge. b)Hang it over the gunwal

Tcecarenko [31]

Answer:

A rag contaminated with gasoline is considered a hazard waste. The question seems to be asked to ask for indications of rag disposal on a ship, and if so, the answer is d) Discard it on land BUT with special precautions

Explanation:

Gasoline is a highly flammable organic solvent that is used as fuel. For the above is a dangerous substance. while the ship reaches the mainland, the rag must be stored avoiding contact with environmental agents such as the sun, pets or food. Once in a dry land the rag can be delivery for accurate disposal.

I hope my answer helps you

6 0

3 years ago

Assuming constant pressure, rank these reactions from most energy released by the system to most energy absorbed by the system,

givi [52]

Answer: The order from the Most energy released to most Energy Absorbed Is given as 2---> 4--->,3-->---> 1

B)-61.9 kJ

Explanation:

The change in the internal energy of a system is positive if the reaction absorbs energy and negative if the reaction releases energy. For a system to cause an increase in volume, it must have very high energy built up to be released.

1. Surroundings get colder and the system decreases in volume. Here, the surrounding absorbs energy resulting in positive ΔE

2. Surroundings get hotter and the system expands in volume. Here energy is released causing the system to be negative

3. Surroundings get hotter and the system decreases in volume. Although there is a decreased volume, the system is negative because it releases energy

4. Surroundings get hotter and the system does not change in volume. System is negative because it releases energy even thgoygh there is no change in volume

Therefore the order from the Most energy released to most Energy Absorbed Is given as 2---> 4--->,3-->---> 1

b) Using

ΔE = q+ w from 1st law of thermodynamics

ΔE= ΔH - P ΔV

gIven

ΔH = -75.0KJ

volume= A change from 5.0L TO 2.0L = Final volume - initial volume = 2-5= -3.00L

P= 43.0atm

ΔE= ΔH - P ΔV

P ΔV = 43 atm x -3 = -129L.atm

We first convert L-atm to Joules.

1 L-atm = 101.325 Joules.

129L.atm = 129 x 101.325 = - 13071 J

to KJ becomes

13071/1000 = - 13.071KJ

Recall ΔE= ΔH - P ΔV and putting values

ΔE = -75.0 - (-13.071 KJ)= -75.0 kJ + 13.071 kJ = -61.9 kJ

8 0

3 years ago