1.008x10^16 Joules. Technically a theory and not a law. but E=MC^2!
energy=mass ×speed of light squared.
J=kg×(m/s)^2
It is a Compound. have a nice day
Well the molar mass of CO2 would be that 1 mol of CO2 would have the mass of 44.0 grams. So 11 mol of CO2 would have 11 • 44 or 484 grams.
Answer:
Explanation:
Given that:
The argon atoms are excited into an excited state before emitting the 488.0 nm laser.
the energy of the first ionization energy of argon is 1520 kJ mol-1.
SInce 1 eV = 96.49 kJ/mol
Therefore, the energy of the first ionization energy of argon in eV is = ( 1520/ 96.49) eV
= 15.75 eV
To find where the energy level of the excited state lies below the vacuum energy level, let's first determine, the energy liberated by using planck expression.





Converting Joules (J) to eV ; we get,

E = 2.53 eV
The energy levels of the first exited state = -13.223 eV
It is a covalent bond. Whenever a compound uses such suffixes like mono, di, tri, tetra, and so on, it is a covalent compound- thus having covalent bonds.