Answer:
8000000 litres
Explanation:
General formula,
→ 1 megaliter = 1000000 litres
Then 8 megaliters will be,
→ 8 × 1000000
→ [ 8000000 litres ]
Hence, the solution is 8000000 L.
Answer:
0.628 M.
Explanation:
In order to solve this problem we need to keep in mind the<em> definition of molarity</em>:
- Molarity = moles / liters
We are given both the <em>number of moles and the volume of solution</em>, meaning we can now proceed to <u>calculate the molarity</u>:
- Molarity = 0.220 mol / 0.350 L
Answer:
76.9L
Explanation:
Based on the graph, whenever the temperature increases by 100K, the volume increases by 10L, so do 769/10
When The balanced equation is:
2Al + 3CuCl2 ⇒3 Cu + 2AlCl3
So, we want to find the limiting reactant:
1- no. of moles of 2Al = MV/n = (Wt * V )/ (M.Wt*n*V) = Wt / (M.Wt *n)
where M= molarity, V= volume per liter and n = number of moles in the balanced equation.
by substitute:
∴ no. of moles of 2Al = 0.2 / (26.98 * 2)= 0.003706 moles.
2- no.of moles of 3CuCl2= M*v / n = (0.5*(15/1000)) / 3= 0.0025 moles.
So, CuCl2 is determining the no.of moles of the products.
∴The no. of moles of 3Cu = 0.0025 moles.
∴The no.of moles of Cu= 3*0.0025= 0.0075 moles.
and ∵ amount of weight (g)= no.of moles * M.Wt = 0.0075 * M.wt of Cu
= 0.0075 * 63.546 =0.477 g
