Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
If a line is parallel to another line,Then the gradients are the same.So m=4 .Using general formula for str8 line, y=mx+c
sub in coorfinates (1,13)
So C=9.
Divide both 6 and 10 by 2 to get 3/5
Multiply both 6 and 10 by 2 to get 12/20
We have to convert 2% in to a decimal then multiply it into the x-value which is the months with the addition of 500 because that is the start value.If you were to graph this it would be a linear fuction, y=0.2x+500. The rate of change is found by slope, so rise over run. taking 2 points on the graph and do this
(y 2-y 1)/(x 2-x 1) and graph the equation and get two of the points and find the slope for the rate of change.
Any number from -10 to -∞ would be correct. One example is -79.
