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inn [45]
3 years ago
7

If p(a|b) = 0.35, p(b) = 0.75 and p(a) = 0.44 are the events a and b independent ?

Mathematics
1 answer:
MatroZZZ [7]3 years ago
6 0
Hello : 
note 1 : 
 p(A|B) = p(A∩B)/<span> p(B)

note 2 : 
</span> A and B independent: p(A∩B) = p(A)×p(B)
calculate : p(A∩B)
p(A∩B) = p(A|B)×p(B)
p(A∩B) = 0.35 ×0.75 = 0.2625
but :  p(A)×p(B) = 0.44×0.75 = 0.33
 conclusion : 
<span>the events A and B  are not  independent ?</span>
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3 years ago
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4 years ago
Read 2 more answers
Show work please for number 2
Pavlova-9 [17]

The combined distance between CD and DE is CE, so...

2x+4 + 6 = x+14   Simplify like terms..

2x + 10 = x + 14      Subtract x from both sides..

x + 10 = 14    Subtract 10 from both sides...

<h2><u><em>x = 4</em></u></h2>

Proof: 2 (4) + 4 + 6 = 4 + 14

       8 + 10 = 18

    <em> Check</em>

5 0
3 years ago
Can someone help me figure out the answer?
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Answer:

f(t) = 5×0.87^t

Step-by-step explanation:

The general form for an exponential function described in this fashion is ...

... f(t) = (starting value) × (1 + (percent change))^t

Here, the "percent change" is -13%, or -0.13.

Then the value (1 + percent change) is (1 + (-0.13)) = 0.87. Putting this and the starting value into the form above, we have ...

... f(t) = 5 × 0.87^t

3 0
3 years ago
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