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asambeis [7]
3 years ago
5

Factor this equation 4-49w^2

Mathematics
1 answer:
OLEGan [10]3 years ago
8 0
4-49w^2=\ \ \ \ | use\ fromula\  (a^2-b^2)=(a-b)(a+b)\\\\
4-49w^2=(2^2-(7w)^2)=(2-7w)(2+7w)\\\\
after\ factorisation:
\ 4-49w^2=(2-7w)(2+7w)
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Let f(x)=x^2- 3. 1. Show that [0, 2] is a bracketing interval for f 2. Carry out 3 iterations of the bisection method applied to
Papessa [141]

Answer:

root estimate = 1.75

error bound = 0.25

Step-by-step explanation:

f is a polynomial, so it is continuous in R (real numbers). Then you can use Bolzano's theorem.

f(0) = -3.1 < 0

f(2) = 4 - 3.1 = 0.9 > 0

Then there exists c in [0, 2], for which f(c) = 0

In the bisection method you generate a sequence x_n of approximations of a root. If you have a bracketing interval [a, b], such that

f(a) and f(b) have opposite signs, then you use  approximate the root as x_n = \frac{a+b}{2}

In this case:

x_0 = 1

f(0)

Then:

x_1=1.5\\f(1.5)0\\

x_2= \frac{(1.5 + 2)}{2}= 1.75

The error bound is half the width of the interval [1.5, 2]

|error| < 0.25

3 0
3 years ago
Initially a ship and a submarine are stationary at sea level, positioned 1.78km apart. The submarine then manoeuvres to position
poizon [28]
I’m assuming ‘dives further’ means to go directly down

the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.

let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)

then this become a simple trig problem:

A)

Let O be the position of of the ship, and C be the original position of the submarine.

therefore, not considering direction

|OC| = 1.78km = 1780m

|CA| = 45m

these are the adjacent and opposite sides of a right angled triangle.

But tan($) = opp/adj = |CA|/|OC| = 45/1780

therefore $ = arctan(45/1780) which is roughly 1.45 degrees,

B)

similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m


tan(¥) = 107/1780

¥ = arctan(107/1780) which is roughly 3.44 degrees






4 0
3 years ago
the student to teacher ratio is 15:3. if there are 90 teachers at the school, how many students are there
mixas84 [53]
15x+3x=90\\&#10;18x=90\\&#10;x=5\\\\&#10;15x=15\cdot5=\boxed{75}
8 0
3 years ago
Read 2 more answers
Sam wants to buy 8 pencils and 6 pens, which cost a total of $8.50. He realizes he doesn't have enough cash and instead takes on
Diano4ka-milaya [45]
X = pencils, y = pens

8x + 6y = 8.50
4x + 4y = 5.....multiply by -2
----------------
8x + 6y = 8.50
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-----------------add
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y = -1.50 / -2
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4x + 4y = 5
4x + 4(0.75) = 5
4x + 3 = 5
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x = 2/4
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Answer:

Step-by-step explanation:

3 0
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