3 years ago

Find the midpoint of (1,8) and (9,6)

Mathematics

1 answer:

Anon25 [30]3 years ago

4 0

Answer:

(5,7)

Step-by-step explanation:

(1,8)

(9,6)

x+x= 9+1=10

y+y= 8+6=14

ans. divide by 2

(5,7)

You might be interested in

Which of the following is the additive identity of 5+2i

Alex17521 [72]

Answer:

Can you take a picture of the question so i could help!

Step-by-step explanation:

7 0

3 years ago

Simple question but im stuck. please help

Dimas [21]

-x+6 ??? im not 100% sure

8 0

3 years ago

Read 2 more answers

Please answer all three questions Pleaseeeeee tysmm <3

oee [108]

Answer: 2 3/4 > 2.68 is correct (only)

Step-by-step explanation: 2 3/4 = 2.75, and 2.75 is greater than 2.68

The rest are incorrect. 7.895 * 10^2 (100) = 789.5, and 5.43 * 10^3 (1000) = 5430. So 789.5 > 5430 is false.

Sqrt(63) = 7.93, and 7.93 > 8.11 is false.

Absolute values ( | | ) mean that no matter if it is negative or positive, it will become positive (unless the negative sign is outside the absolute value). 1.5 > 3.2 is false, and even without the absolute value, -1.5 is still less than 3.2

6 0

2 years ago

What is the missing angle? 133, 26 , ?

SCORPION-xisa [38]

21 because a triangle is always going to equal 180 so add those then subtract and it’s 21

7 0

3 years ago

Help:<br> <img src="https://tex.z-dn.net/?f=1.%5C%20%26x%5E4-61x%5E2%2B900%3D0%20%5C%5C%202.%20%5C%20%26%20x%5E4-25x%5E2%2B144%3

yawa3891 [41]

$\bf{1) \ x^4-61x^2+900=0 }$

Applying the factorization method, for example:

$\bf{ 0=(x^2)^2-61(x^2)+900=(x^2-36)(x^2-25)}$

$\bf{\\ &=(x+6)(x-6)(x+5)(x-5); }$

$\bf{ x_1=6 \quad x_2=-6 \quad \ \ \ x_3=5 \quad x_4=5 }$

$\bf{2) \ x^4-25x^2+144=0 }$

Applying the factorization method:

$\bf{0&=(x^2)^2-25(x^2)+144=(x^2-16)(x^2-9) }$

$\bf{ =(x-4)(x+4)(x-3)(x+3); }$

$\bf{ x_1=4 \quad x_2=-4 \quad x_3=3 \quad x_4=-3 }$

7 0

1 year ago