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3 years ago

Can you give me the answers to this

Mathematics

1 answer:

Virty [35]3 years ago

3 0

This is the site i use for textbooks and worksheets
http://www.slader.com/subject/math/algebra/textbooks/

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8/3 X 7/10 X 6/1 plz help me

Harlamova29_29 [7]

Answer:

are you mutiplying?

Step-by-step explanation:

5 0

3 years ago

A train leaves at 14.54 and arrives at its destination at 15.47. If the train travelled 66 km, what was it's average speed in km

JulijaS [17]

Answer: average speed of the train = 4,483.0 km/h

Step-by-step explanation:

Speed = Distance / Time

Distance = 66 km

Time = 15.47 cancelling 15, we have 60 sec added to 47 sec

- 14.54

= 14. 107 60 + 47

- 14. 54

53secs

53secs to hours becomes =

60 secs = 1 min

60 min= i hour

therefore 53seconds =53/3600=0.0147222hours

Speed= 66/ 0.0147222= 4,483.025

Rounding to 1 dp becomes= 4,483.0 km/h

3 0

3 years ago

The value of

marusya05 [52]

$\large\underline{\sf{Solution-}}$

We have to find out the value of the fraction.

Let us assume that:

$\sf \longmapsto x =2 + \dfrac{1}{2 + \dfrac{1}{2 + \dfrac{1}{2 + ... \infty} } }$

We can also write it as:

$\sf \longmapsto x =2 + \dfrac{1}{x}$

$\sf \longmapsto x =\dfrac{2x + 1}{x}$

$\sf \longmapsto {x}^{2} =2x + 1$

$\sf \longmapsto {x}^{2} - 2x - 1 = 0$

Comparing the given equation with ax² + bx + c = 0, we get:

$\sf \longmapsto\begin{cases} \sf a =1 \\ \sf b = - 2 \\ \sf c = - 1 \end{cases}$

By quadratic formula:

$\sf \longmapsto x = \dfrac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

$\sf \longmapsto x = \dfrac{2 \pm \sqrt{ {( - 2)}^{2} - 4(1)( - 1)} }{2 \times 1}$

$\sf \longmapsto x = \dfrac{2 \pm \sqrt{4 + 4} }{2 \times 1}$

$\sf \longmapsto x = \dfrac{2 \pm \sqrt{8} }{2}$

$\sf \longmapsto x = \dfrac{2 \pm2 \sqrt{2} }{2}$

$\sf \longmapsto x = 1 \pm\sqrt{2}$

$\sf \longmapsto x = \begin{cases} \sf 1 + \sqrt{2} \\ \sf 1 - \sqrt{2} \end{cases}$

But "x" cannot be negative. Therefore:

$\sf :\implies x = 1 + \sqrt{2}$

So, the value of the fraction is 1 + √2.

4 0

2 years ago

A new sample of 225 employed adults is chosen. Find the probability that less than 7.1% of the individuals in this sample hold m

arsen [322]

Answer:

The probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

Step-by-step explanation:

Let X = number of individuals in the United States who held multiple jobs.

The probability that an individual holds multiple jobs is, p = 0.13.

The sample of employed individuals selected is of size, n = 225.

An individual holding multiple jobs is independent of the others.

The random variable X follows a Binomial distribution with parameters n = 225 and p = 0.13.

But since the sample size is too large Normal approximation to Binomial can be used to define the distribution of proportion p.

Conditions of Normal approximation to Binomial are:

np ≥ 10
n (1 - p) ≥ 10

Check the conditions as follows:

$np=225\times 0.13=29.25>10\\n(1-p)=225\times (1-0.13)=195.75>10$

The distribution of the proportion of individuals who hold multiple jobs is,

$p\sim N(p, \frac{p(1-p)}{n})$

Compute the probability that less than 7.1% of the individuals in this sample hold multiple jobs as follows:

$P(p$

*Use a z-table.

Thus, the probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

7 0

3 years ago

Over the last three evenings, Debra received a total of 110 phone calls at the call center. The second evening, she received 4 t

Elza [17]

Answer:

See below.

Step-by-step explanation:

Total = 110

Let calls on third evening = x

second evening = 4x

first evening = x + 8

=> x + 4x + x + 8 = 110

=> 6x = 102

=> x = 17

First evening = x = 17 calls

Second evening = 4x = 68 calls

Third evening = x + 8 = 25 calls

4 0

2 years ago