We can split this up into 3 rectangles. 2 vertical ones (8 x 3) and one horizontal one in the middle (5 x (8 - 5)
8 x 3 = 24
24 x 2 = 48
5 x (8-5) = 5 x 3 = 15
now add 48 + 15 = 63 cm^2
Divide -3
-3/-3a = 15/-3
a = -5
Since triangle ABC is isosceles, then angles 1 and 9 are congruent.
4x + 3 = 9x - 47
-5x = -50
x = 10
m<1 = 4x + 3 = 40 + 3 = 43
m<1 = m<9 = 43
Triangle DBE is equilateral, so it is also equiangular.
m< 4 = m<5 = m<6 =60
Angles 3 and 8 are supplementary to congruent angles that measure 60 deg, so 180 - 60 = 120, so
m<3 = m<8 = 120
For angles 2 and 7, use the sum of the measures of the angles of a triangle is 180 deg.
m<1 + m<2 + m<3 = 180
43 + m<2 + 120 = 180
m<2 + 163 = 180
m<2 = 17
m<2 = m<7 = 17
Answer:
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