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2 years ago

14

Analyze the graph below and answer the question that follows. / What is the angle of rotation from RST to R'S'T' ? Assume that t

he center of rotation is the origin. A. 180° clockwise B. 90° clockwise C. 90° counterclockwise D. 270° counterclockwise

1 answer:

liberstina [14]2 years ago

6 0

Answer:

C

Step-by-step explanation:

This could be either 90° counterclockwise or 270° clockwise but the latter is not an option so the answer is C.

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Plz help ill give brainlist to you

Lelu [443]

0.4% of $4,800 is $19.2, otherwise written as $19.20 in terms of money, apparently. This is based off the calculations of a calculator, though if you prefer to do the rough work, be my guest. The work for finding it on raw work is below.

(EX.) EQUATION : y = p% × x
EQUATION : y = 0.4% × 4800

To make this work, you gotta convert that percent into a decimal, by dividing the percentage by 100. 0.4 ÷ 100 = 0.004

EQUATION : y = 0.004 × 4800.

Once you multiply them, you get : 19.2 (otherwise known as $19.20)

6 0

3 years ago

The process of selecting elements from a population, collecting data from them, and using it as representative of all those a re

IrinaVladis [17]

Answer:

Step-by-step explanation:

i don't know sorry

5 0

2 years ago

In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,

aivan3 [116]

Answer:

Case 1:

$AB = 30$

$BC = 50$

Case 2:

$AB = 15.9$

$BC = 36.7$

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

$AB^2 = AN^2 + BN^2$

This gives:

$AB^2 = 24^2 + 18^2$

$AB^2 = 576 + 324$

$AB^2 = 900$

Take square roots of both sides

$AB = \sqrt{900$

$AB = 30$

To calculate BC, we consider ANC, where:

$AC^2 = AN^2 + NC^2$

$40^2 = 24^2 + NC^2$

$1600 = 576 + NC^2$

Collect like terms

$NC^2 = 1600 - 576$

$NC^2 = 1024$

Take square roots

$NC = \sqrt{1024$

$NC = 32$

So:

$BC = NC + BN$

$BC = 32 + 18$

$BC = 50$

Case 2:

Using Pythagoras theorem in ANB, we have:

$AN^2 = AB^2 + BN^2$

This gives:

$24^2 = AB^2 + 18^2$

$576 = AB^2 + 324$

Collect like terms

$AB^2 = 576 - 324$

$AB^2 = 252$

Take square roots of both sides

$AB = \sqrt{252$

$AB = 15.9$

To calculate BC, we consider ABC, where:

$AC^2 = AB^2 + BC^2$

$40^2 = 252 + BC^2$

$1600 = 252 + BC^2$

Collect like terms

$BC^2 = 1600 - 252$

$BC^2 = 1348$

Take square roots

$BC = \sqrt{1348$

$BC = 36.7$

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0

2 years ago

How much water does it take to completely fill a pool that is 50m long, 25m wide, and 2 m deep?

viktelen [127]

Answer:

which is the volume of the water

it implies , volume=l*b*h

50m*25m*2m

2500m'3

6 0

3 years ago

Read 2 more answers

Solve the following equation for 0°≤x≤360° : 2 cot 2x + 3 = 0

evablogger [386]

Answer:

π

2

,

3

⋅

π

2

,

3

⋅

π

4

,

7

⋅

π

4

Explanation:

Factorizing your equation we get

cot

(

x

)

=

0

so

cos

(

x

)

=

0

we get the following Solutions in the given interval

x

=

π

72

or

x

=

3

π

2

for the second case we get

cot

(

x

)

=

−

1

so

cos

(

x

)

=

−

sin

(

x

)

and we get

x

=

3

π

4

or

x

=

7

π

4

Hint:

To get the Solutions of the last equation you can use

√

sin

(

x

+

π

4

)

=

0

Step-by-step explanation:

3 0

2 years ago