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ikadub [295]
2 years ago
14

Analyze the graph below and answer the question that follows. / What is the angle of rotation from RST to R'S'T' ? Assume that t

he center of rotation is the origin. A. 180° clockwise B. 90° clockwise C. 90° counterclockwise D. 270° counterclockwise

Mathematics
1 answer:
liberstina [14]2 years ago
6 0

Answer:

C

Step-by-step explanation:

This could be either 90° counterclockwise or 270° clockwise but the latter is not an option so the answer is C.

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Another prize for people<br> will mark them as brainiest if correct only
Fantom [35]

Answer:

wat is the quistion

Step-by-step explanation:

8 0
2 years ago
3) At a school several teachers were holding a contest to see which class could earn the most trivia points. Mrs. Clawson's clas
Snezhnost [94]

Answer:

Mean: 89

Median: 90

Mode: 94

Range: 12

5 0
2 years ago
During a period of 112 minutes, a music station played 40 minutes of commercials. What
Gemiola [76]

Answer:

9:5

Step-by-step explanation:

  1. 112 - 40 = 72. 112 represents the total time, but you are comparing music to commercials, so you have to subtract the commercial time from the total time.
  2. Find the GCF of 72 and 40, which is 8.
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5 0
2 years ago
3.7 x 10 to the power of 2​
bekas [8.4K]

Answer:

1369

Step-by-step explanation:

3.7 x 10 = 37 x 37 = 1369

8 0
2 years ago
(1 point) The distribution of heights of adult men in the U.S. is approximately normal with mean 69 inches and standarddeviation
Ludmilka [50]

Part a)

The mean height is 69 inches with a standard deviation of 2.5 inches.

If we consider a interval of heights that relies on no more than two standard deviations from the mean, we will cover, approximatelly, 95% of men's heights. Then, we interval that we're looking for is:

Answer: 64 TO 74 INCHES

Part b)

Since [69,74] is half of the interval in the previous answer, we might expect half of 95% as the percentage of men who are in this interval. That is:

Answer: 47.5 PERCENT

Part c)

A interval of heights that relies on no more than one standard deviation from the mean covers, approximatelly, 68% of men's heights. Then, we can consider that the percentage of men that are between 64 and 66.5 inches is given by 47.5 - 68/2 = 13.5.

Answr: 13.5 PERCENT

3 0
1 year ago
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