To do the first question, simplify the equation, putting like terms together, by adding and subtracting to do this.
Then looking at the equation that you solved for, look and see if there are any other equations that are related in some way to the original solved equation.
Pay close attention to the positive and negative signs.
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
2+2=4 quick mafs
Step-by-step explanation:
The area of a trapezoid with base lengths 7 in and 19 in is given by
A = (1/2)(b1 + b2)h
A = (1/2)(7 +19)·7 = 91
The appropriate choice is
D. 91 in²
_____
It can also be figured by adding the area of the 7 in square (49 in²) to the area of the 7×12 in right triangle (42 in²).
Answer: There are 20 boys
Step-by-step explanation:
