Answer:
Tienes 3 números, "x", "y", "z"
=> El primero es 20 unidades menor que el segundo:
El primero es "x", y el segundo es "y", entonces:
x = y - 20
=> El tercero es igual a la suma de los dos primeros:
El tercero es "z", entonces:
z = x + y
z = (y - 20) + y
z = 2y - 20
=> Entre los tres suman 120
x + y + z = 120
y - 20 + y + 2y - 20 = 120
4y - 40 = 120
4y = 160
y = 40
Si y = 40, entonces:
x = y - 20
x = 20
Además, z = 2y - 20
z= 60
RPTA:
x=20
y=40
z=60
Step-by-step explanation:
3x - y = 0 . . . (1)
5x + 2y = 22 . . . (2)
From (1), y = 3x . . . (3)
Putting (3) into (2) gives:
5x + 2(3x) = 22
5x + 6x = 22
11x = 22
x = 2
From (3), y = 3(11) = 33
x = 11, y = 33.
It would be d , because the lowest number which is your (min) is 72 the highest number which is your (max) is 93 . Your median would be 85 because you would add 84 & 86 and in result you would get 170 then you would divide by 2 and get 85 . Your Q1 would be 76 and your Q3 would be 91 , there is 10 numbers in total separate them (72,74,76,83,84) and (86,89,91,92,93) then find the middle number in each
Hope this helps !
