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just olya [345]
3 years ago
15

Suppose the speeds of vehicles traveling on a highway are normally distributed and have a known population standard deviation of

7 miles per hour and an unknown population mean. A random sample of 32 vehicles is taken and gives a sample mean of 64 miles per hour. Find the margin of error for the confidence interval for the population mean with a 98% confidence level.
Mathematics
1 answer:
erik [133]3 years ago
5 0

Answer:

2.88

Step-by-step explanation:

Data provided in the question

\sigma = Population standard deviation = 7 miles per hour

Random sample = n = 32 vehicles

Sample mean = \bar X = 64 miles per hour

98% confidence level

Now based on the above information, the alpha is

= 1 - confidence level

= 1 - 0.98

= 0.02

For \alpha_1_2 = 0.01

Z \alpha_1_2 = 2.326

Now the margin of error is

= Z \alpha_1_2 \times \frac{\sigma}{\sqrt{n}}

= 2.326 \times \frac{7}{\sqrt{32}}

= 2.88

hence, the margin of error is 2.88

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