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aniked [119]
3 years ago
12

What are the foci of the hyperbola with equation 5y^2-4x^2=20?

Mathematics
2 answers:
shusha [124]3 years ago
5 0
The foci of the hyperbola with equation 5y^2-4x^2=20 will be given as follows:
divide each term by 20
(5y^2)/20-(4x^2)/20=20/20
simplifying gives us:
y^2/4-x^2/5=1
This follows the standard form of the hyperbola
(y-k)²/a²-(x-h)²/b²=1
thus
a=2, b=√5 , k=0, h=0
Next we find c, the distance from the center to a focus.
√(a²+b²)
=√(2²+(√5)²)
=√(4+5)
=√9
=3
the focus of the hyperbola is found using formula:
(h.h+k)
substituting our values we get:
(0,3)
The second focus of the hyperbola can be found by subtracting c from k
(h,k-c)
substituting our values we obtain:
(0,-3)

Thus we have two foci
(0,3) and (0,-3)
ExtremeBDS [4]3 years ago
3 0
(0 <span>±</span> 3) is the answer to your question? Hope this helps
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Dominik [7]

Answer:

1) y = 5/2x - 3/2

2) y = 2/5x - 4/5

Step-by-step explanation:

1)

(1, 1) and (3, 6)

m = (y2 - y1)/(x2 - x1)

m= (6 - 1)/(3-1)

m= 5/2

m= 5/2

y - y1 = m(x - x1)

y - 1 = 5/2(x - 1)

y - 1 = 5/2x - 5/2

y = 5/2x - 3/2

2)

(2, 0) and (7, 2)

m = (y2 - y1)/(x2 - x1)

m= (2 - 0)/(7 - 2)

m = 2/5

y - y1 = m(x - x1)

y - 0 = 2/5(x - 2)

y = 2/5x - 4/5

5 0
2 years ago
Read 2 more answers
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DochEvi [55]
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6 0
3 years ago
I am thinking of a number. i will add four and then multiply it by five. the answer will be thirty five. whats the number?
kodGreya [7K]

Answer:

B. 3

Step-by-step explanation:

Let's make an equation for this. Our unknown number is x.

x

We are adding 4.

x + 4

Then multiplying by 5.

(x + 4) • 5

It will equal 35.

(x + 4) • 5 = 35

To solve this, divide both sides by 5.

(x + 4) = 7

Now subtract 4 from both sides.

x = 3

This is your answer.

Check this by plugging it back into our original equation.

(x + 4) • 5 = 35

(3 + 4) • 5 = 35

7 • 5 = 35

35 = 35

Your answer is correct.

Hope this helps!

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Step-by-step explanation:

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