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3 years ago

Does anyone no the answer

Chemistry

1 answer:

gulaghasi [49]3 years ago

6 0

In terms of naming organic compounds, always identify the longest parental chain in the molecule first.

For the first it would have 3 carbons

Next number the carbons to give you the substituents the quickest.

For instance for number 1, it does not matter, but for number 2, you would start numbering the carbons from the left compared to the right, because if you number from the left

The methyl group appears immediately after, on 2nd carbon, but if you number from the right, it appears on the 3rd.

Always number to give the lowest position or numbering of the substituents.

1. 2-methylpropane
2. 2,4 - dimethylhexane
3. 2,5 - dimethylheptane

Please provide brainliest.

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Rashid [163]

Answer:

The temperature is 30,92K

Explanation:

We use the formula PV=nRT. We convert the unit of pressure in kPa into atm.

101,325kPa----1atm

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PV=nRT---->T= (PV)/(RT)

T=(1,2 atm x 3L)/(1,42 mol x 0,082 l atm/K mol )= 30, 91721058 K

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4 years ago

A gas is allowed to expand from a volume of 400 ml to 2000 ml at a constant temperature. If the the initial pressure is 3 atm, c

Lostsunrise [7]

Answer:

$P_{2}) = 0.6 \; atm$

Explanation:

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To find the final pressure P2, we would use Boyles' law.

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

$PV = K$

$P_{1}V_{1} = P_{2}V_{2}$

Substituting into the equation, we have;

$3 * 400 = P_{2}* 2000$

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3 years ago

a water sample is found to have a cl- content of 100ppm as nacl what is the concentration of chloride in moles per liter

ladessa [460]

Answer:

The concentration of chloride ion is $2.82\times10^{-3}\;mol/L$

Explanation:

We know that 1 ppm is equal to 1 mg/L.

So, the $Cl^-$ content 100 ppm suggests the presence of 100 mg of $Cl^-$ in 1 L of solution.

The molar mass of $Cl^-$ is equal to the molar mass of Cl atom as the mass of the excess electron in $Cl^-$ is negligible as compared to the mass of Cl atom.

So, the molar mass of $Cl^-$ is 35.453 g/mol.

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Hence, the number of moles (N) of $Cl^-$ present in 100 mg (0.100 g) of $Cl^-$ is calculated as shown below:

$N=\frac{0.100\;g}{35.453\;g/mol}=2.82\times 10^{-3}\;mol$

So, there is $2.82\times10^{-3}\;mol$ of $Cl^-$ present in 1 L of solution.

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4 years ago

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ExtremeBDS [4]

Answer:

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3 years ago