<span>N2 + 3H2 → 2 </span>NH3<span> from bal. rxn., 2 moles of </span>NH3<span> are formed per 3 moles of </span>H2, 2:3 moleH2<span>: 3.64 </span>g<span>/ 2 </span>g<span>/mole </span>H2<span>= 1.82 1.82 moles </span>H2<span> x 2/3 x 17
</span>
The answer is 492.8 g
1. Calculate a number of moles of a sample.
2. Calculate a molar mass of C3H8.
3. Calculate a mass of the sample.
1. Avogadro's number is the number of units (atoms, molecules) in 1 mole of substance: 6.023 × 10²³ units per 1 mole
6.023 × 10²³ atoms : 1 mol =6.72 × 10²⁴ atoms : n
n = 6.72 × 10²⁴ atoms * 1 mol : 6.023 × 10²³ atoms = 1.12 × 10 mol = 11.2 mol
2. Molar mass (Mr) of C3H8 is sum of atomic masses (Ar) of its elements:
Ar(C) = 12 g/mol
Ar(H) = 1 g/mol
Mr(C3H8) = 3 * Ar(C) + 8 * Ar(H) = 3 * 12 + 8 * 1 = 36 + 8 = 44 g/mol
3. Mass (m) of a sample is number of moles (n) multiplied by molar mass (Mr) of C3H8:
m = n * Mr = 11.2 mol * 44 g/mol = 492.8 g
Reaction arrows are used to describe the state or progress of a reaction. 2.1 The Chemical Reaction Arrow. The chemical reaction arrow is one straight arrow pointing from reactant(s) to product(s) and by-products, sometimes along with side products. A → B. It is the most widely used arrow.
Boron is a chemical element with the symbol B and atomic number 5. Produced entirely by cosmic ray spallation and supernovae and not by stellar nucleosynthesis, it is a low-abundance element in the Solar System and in the Earth's crust
The C5 (C5) fraction is a co-product of naphtha cracking and is used as a raw material for synthetic rubber and petroleum resins.
Deuterium
Deuterium is frequently represented by the chemical symbol D. Since it is an isotope of hydrogen with mass number 2, it is also represented by 2. H. .
Unimolecular Elimination (E1) is a reaction in which the removal of an HX substituent results in the formation of a double bond. It is similar to a unimolecular nucleophilic substitution reaction (SN1) in various ways. One being the formation of a carbocation intermediate.
Aqueous (aq.): In the presence of water, often meaning water is the solvent. Aqueous NaCl. Anhydrous NaCl.
Hydrogen is the chemical element with the symbol H and atomic number 1. ... Since hydrogen readily forms covalent compounds with most nonmetallic elements, most of the hydrogen on Earth exists in molecular forms such as water or organic compounds.
Catalyst, in chemistry, any substance that increases the rate of a reaction without itself being consumed. Enzymes are naturally occurring catalysts responsible for many essential biochemical reactions.
Kp is the equilibrium constant calculated from the partial pressures of a reaction equation. It is used to express the relationship between product pressures and reactant pressures. It is a unitless number, although it relates the pressures.
Hope this helps a bit?
Answer : The molar mass of unknown substance is, 39.7 g/mol
Explanation : Given,
Mass of unknown substance = 9.56 g
Volume of solution = 100.0 mL
Molarity = 2.41 M
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
Now put all the given values in this formula, we get:
Therefore, the molar mass of unknown substance is, 39.7 g/mol
Answer:
1. q.
2. 2q.
3. 3q.
4. 6q.
Explanation:
We'll begin by calculating the specific heat capacity of the liquid. This can be obtained as follow:
Mass (m) = 25 g
Change in temperature (ΔT) = 20 °C
Heat (Q) = q
Specific heat capacity (C) =?
Q = MCΔT
q = 25 × C × 20
q = 500C
Divide both side by 500
C = q/500
C = 2×10¯³ qg°C
Therefore, the specific heat capacity of liquid is 2×10¯³ qg°C
Now, we shall determine the heat required to produce the various change in temperature as follow:
2. Mass (m) = 50 g
Change in temperature (ΔT) = 20 °C
Specific heat capacity (C) = 2×10¯³ qg°C
Heat (Q) =?
Q = MCΔT
Q = 50 × 2×10¯³ × 20
Q = 2q.
Therefore, the heat required is 2q.
3. Mass (m) = 25 g
Change in temperature (ΔT) = 60 °C
Specific heat capacity (C) = 2×10¯³ qg°C
Heat (Q) =?
Q = MCΔT
Q = 25 × 2×10¯³ × 60
Q = 3q.
Therefore, the heat required is 3q.
4. Mass (m) = 50 g
Change in temperature (ΔT) = 60 °C
Specific heat capacity (C) = 2×10¯³ qg°C
Heat (Q) =?
Q = MCΔT
Q = 50 × 2×10¯³ × 60
Q = 6q.
Therefore, the heat required is 6q.
