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3 years ago

Can anyone help me with any of the questions

Chemistry

1 answer:

Dafna11 [192]3 years ago

7 0

Use the chart to help you look carefully at the numbers and the volumes to figure the questions out hope this helps

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1.2 moles of (NH4)3PO3

Aleks04 [339]

1.2 moles of (nph4)3po3 is.......159.6 grams

3 0

3 years ago

How many atoms are in a solid piece of iron that has a mass of 24.0g?

Julli [10]

Atomic mass iron ( Fe ) = 55.84 a.m.u

55.84 g ------------ 6.02x10²³ atoms
24.0 g ------------- ??

24.0 x ( 6.02x10²³) / 55.84

=> 2.58x10²³ atoms

5 0

4 years ago

Emission Spectrum Questions for Quiz Print - Quizizz

-Dominant- [34]

Isotopes of the same element

₃₅⁷⁷X and ₃₅⁸¹X

<h3>Further explanation</h3>

Given

Isotopes of element

Required

Isotopes of the same element

Solution

The elements in nature have several types of isotopes

Isotopes are elements that have the same Atomic Number (Proton) and different mass numbers

Element symbols that meet the 2 conditions above are :

₃₅⁷⁷X and ₃₅⁸¹X

3 0

3 years ago

Need help with this can some please help

vekshin1

I believe you would just put a 2 in front of NH3 and keep the other ones as 1

7 0

3 years ago

For the equilibrium

Mamont248 [21]

Answer:

Equilibrium concentrations of the gases are

$H_2S=0.596M$

$H_2=0.004 M$

$S_2=0.002 M$

Explanation:

We are given that for the equilibrium

$2H_2S\rightleftharpoons 2H_2(g)+S_2(g)$

$k_c=9.0\times 10^{-8}$

Temperature, $T=700^{\circ}C$

Initial concentration of

$H_2S=0.30M$

$H_2=0.30 M$

$S_2=0.150 M$

We have to find the equilibrium concentration of gases.

After certain time

2x number of moles of reactant reduced and form product

Concentration of

$H_2S=0.30+2x$

$H_2=0.30-2x$

$S_2=0.150-x$

At equilibrium

Equilibrium constant

$K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}$

Substitute the values

$9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}$

By solving we get

$x\approx 0.148$

Now, equilibrium concentration of gases

$H_2S=0.30+2(0.148)=0.596M$

$H_2=0.30-2(0.148)=0.004 M$

$S_2=0.150-0.148=0.002 M$

3 0

3 years ago