All categories

2 years ago

Can anyone help me with any of the questions

Chemistry

1 answer:

Dafna11 [192]2 years ago

7 0

Use the chart to help you look carefully at the numbers and the volumes to figure the questions out hope this helps

You might be interested in

Graphing is an important procedure used by scientist to display the data that is collected during a controlled experiment. There

astraxan [27]

Bar graph or bar chart displays data graphically using bars

The correct values are;

1. The independent variable is the month of the year

2. The dependent variable is the number of deer

3. The title is: The number of deer counted per month

The reason the above values are correct are as follows:

In a tabular form is given as follows;

$\begin{array}{|c|cc|}Month&&\# \ of \ deer \\Sept&&38\\Oct&&32\\Nov&&26\\Dec&&20\\ Jan &&15\\Feb&&12\end{array}\right]$

A. Please find attached the required bar graph (chart) created with a desktop application

1. In an investigation to assign the cause of an effect is the cause of an effect, the independent variable is the causal variable responsible for the observed effect, and it is not affected by the effect. It is the variable that is not measured

In the given data, the month of the year is not affected by the number of deer, and it is not counted, to see if there is a change, therefore, the independent variable is the month of the year

2. The dependent variable, is the effect variable that is measured, and it depends on the dependent variable, which is the month

Therefore, the dependent variable is the number of deer

3. An appropriate title is one that captures the information intended to be obtained from the Bar graph

An appropriate title for the bar graph is; The number of deer counted per month

Learn more about graphs here:

brainly.com/question/20465674

brainly.com/question/12730146

4 0

2 years ago

How does temperature affect the state of matter

Tom [10]

Temperature is very important if ice gets too hot it turns to water, if it gets even hotter it turns to gas.

but if it’s too cold water can turn into ice

Temperature determines what state of matter something is

8 0

3 years ago

Magnesium metal reacts with iodine gas at high temperatures to form magnesium iodide. what mass of mgi2 can be produced from the

sergiy2304 [10]

54.8 g of MgI2 can be produced. To solve this, you need to determine the molar mass of each reactant and the product. First, look up the atomic weights of iodine and magnesium Atomic weight of Iodine = 126.90447 Atomic weight of Magnesium = 24.305 Molar mass of MgI2 = 24.305 + 2 * 126.90447 = 278.11394 Now determine how many moles of Iodine and Magnesium you have moles of Iodine = 50.0 g / 126.90447 g/mol = 0.393997154 mole moles of Magnesium = 5.15 / 24.305 g/mol = 0.211890557 mole Since for every magnesium atom, you need 2 iodine atoms and since the number of moles of available iodine isn't at least 2 times the available moles of magnesium, iodine is the limiting reagent. So figure out how many moles of magnesium will be consumed by the iodine 0.393997154 mole / 2 = 0.196998577 mole. This means that you can make 0.196998577 moles of MgI2. Now simply multiply by the previously calculated molar mass of MgI2 0.196998577 mole * 278.11394 g/mole = 54.78805 g Round the result to the correct number of significant figures. 54.78805 g = 54.8 g

5 0

3 years ago

If a proton and electron were 0.40nm apart, predict what the force of attraction might be

Aleks [24]

??????????????????????????????????????????????

3 0

2 years ago

Give the half equation to show what happens to oxygen when it is rusting

ycow [4]

Answer:

½O 2 + 2e - + H 2O → 2OH.

Explanation:

Redox reactions - Higher

In terms of electrons:

oxidation is loss of electrons

reduction is gain of electrons

Rusting is a complex process. The example below show why both water and oxygen are needed for rusting to occur. They are interesting examples of oxidation, reduction and the use of half equations:

iron loses electrons and is oxidised to iron(II) ions: Fe → Fe2+ + 2e-

oxygen gains electrons in the presence of water and is reduced: ½O2 + 2e- + H2O → 2OH-

iron(II) ions lose electrons and are oxidised to iron(III) ions by oxygen: 2Fe2+ + ½O2 → 2Fe3+ + O2-

3 0

2 years ago