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ValentinkaMS [17]
3 years ago
14

Can anyone help me with any of the questions

Chemistry
1 answer:
Dafna11 [192]3 years ago
7 0
Use the chart to help you look carefully at the numbers and the volumes to figure the questions out hope this helps
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3. 79,789kJ = (293k) (377kJ)
KatRina [158]

the anwser would most likely be j=0

5 0
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Balance C2 H602+02 reacts with CO2 + H2O
sergiy2304 [10]

Answer:

Yeah

Explanation:

Mhm

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3 years ago
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A sugar crystal contains approximately 1.4×1017 sucrose (C12H22O11) molecules. What is its mass in milligrams? Express using 2 s
alekssr [168]

Answer:

From the periodic table:

mass of carbon = 12 grams

mass of hydrogen = 1 grams

mass of oxygen = 16 grams

molar mass of surcose = 12(12) + 22(1) + 11(16) = 342 grams

number of molecules = number of moles x Avogadro's number

number of moles = number of molecules / Avogadro's number

number of moles = (2.2x10^17) / (6.02x10^23) = 3.6544 x 10^-7 moles

number of moles = mass / molar mass

mass = number of moles x molar mass

= 1.7 x 10^17/6.022 x 10^23.

5 0
3 years ago
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Which of the following would be produced when two or more different atoms bond chemically?
ExtremeBDS [4]

Answer:

When two or more atoms chemically bond with each other, the resultant chemical structure is a molecule. The familiar water molecule, H2O, consists of two hydrogen atoms and one oxygen atom; these bond together to form water,  irdk but it's either C or D

Explanation:

hope this helps have a good rest of your day :) ❤

7 0
3 years ago
Na2S2O3 + AgBr NaBr + Na3ſAg(S203)2] What is
gtnhenbr [62]

Answer:

Mass of NaBr produced  = 23.67 g

Explanation:

Given data:

Mass of AgBr = 42.7 g

Mass of NaBr produced = ?

Solution:

Chemical equation:

2Na₂S₂O₃ + AgBr    →    NaBr + Na₃(Ag(S₂O₃)₂

Number of moles of AgBr:

Number of moles = mass/molar mass

Number of moles = 42.7 g/ 187.7 g/mol

Number of moles = 0.23 mol

now we will compare the moles of AgBr with NaBr.

             AgBr        :         NaBr

                1            :           1

              0.23       :         0.23

Mass of NaBr:

Mass = number of moles × molar mass

Mass = 0.23 mol × 102.89 g/mol

Mass = 23.67 g

8 0
3 years ago
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