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Dovator [93]
3 years ago
10

Please help me and get me the right answer

Chemistry
1 answer:
weqwewe [10]3 years ago
5 0

Answer:

8.21 × 10^{15} Hz

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Please help . also need the name of their binary ionic compound . ​
madreJ [45]

Answer:

See below!

Explanation:

For the chemical formula, you need to have enough of each atom so that the charge is zero.

Aluminum has a +3 charge, and fluorine has a -1 charge.  Since the charge has to be zero, you need three fluorines, giving you AlF₃.

Barium has a +2 charge, and oxygen has a -2 charge.  Since the charges are equal in magnitude but opposite in sign, you only need one of each atom giving you BaO.

The name of the ionic compound will be the metal and then the nonmetal.  When putting the nonmetal in, change the ending to "-ide".  For example "chlorine" would be "chloride.

CaCl₂  ==>  calcium chloride

Ga₂S₃  ==>  gallium sulfide

K₃N  ==>  potassium nitride

AlF₃ ==>  aluminum fluoride

BaO  ==>  barium oxide

6 0
3 years ago
Which unit can be used to express solution concentration?
katrin2010 [14]

Answer:

mol/L

Explanation:

5 0
3 years ago
A solution of H2SO4(aq) with a molal concentration of 4.80 m has a density of 1.249 g/mL. What is the molar concentration of thi
Naddika [18.5K]
Imagine we have <span>mass of solvent 1kg (1000g)
According to that: </span>molality =n(solute) / m(solvent) =\ \textgreater \  4.8m = 4.8mole / 1kg
= 4.8 mole * 98 g/mole = 470g
m(H2SO4) = n(H2SO4)*Mr(H2SO4) =\ \textgreater \=\ \textgreater \  Molarity = 4.8 mole / 1.2 L = 4 M m(H2SO4)  which is =<span>470g

</span><span>m(solution) = m(H2SO4) + m(solvent) = 470 + 1000 = 1470 g
d(solution) = m(solution) / V(solution) =>
=> 1.249 g/mL = 1470 g / V(solution) =></span>
Molarity = n(solute) / V(solution) =\ \textgreater \
5 0
3 years ago
Is the freezing point of water a physical change or a physical property​
olya-2409 [2.1K]

Answer:

It is a physical change because this change is reversible and no chemical reaction occurs.

Explanation:

3 0
3 years ago
Read 2 more answers
A sample of 28 Mg decays initially at a rate of 53500 disintegrations per minute, but the decay rate falls to 10980 disintegrati
prisoha [69]

Answer : The half life of 28-Mg in hours is, 6.94

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant

t = time passed by the sample = 48.0 hr

a = initial amount of the reactant disintegrate = 53500

a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520

Now put all the given values in above equation, we get

k=\frac{2.303}{48.0}\log\frac{53500}{42520}

k=9.98\times 10^{-2}hr^{-1}

Now we have to calculate the half-life.

k=\frac{0.693}{t_{1/2}}

9.98\times 10^{-2}=\frac{0.693}{t_{1/2}}

t_{1/2}=6.94hr

Therefore, the half life of 28-Mg in hours is, 6.94

8 0
3 years ago
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