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Dovator [93]
3 years ago
10

Please help me and get me the right answer

Chemistry
1 answer:
weqwewe [10]3 years ago
5 0

Answer:

8.21 × 10^{15} Hz

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The value of Ksp for PbCl2 is 1.6 ×10-5. What is the lowest concentration of Cl-(aq) that would be needed to begin precipitation
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0.04 M is the lowest concentration of chloride ions that would be needed to begin precipitation.

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Concentration of lead nitarte = [Pb(NO_3)_2]=0.010 M

Pb(NO_3)_2(aq)\rightleftharpoons Pb^{2+}(aq)+2NO_{3}^{-}(aq0

1 Mole of lead nirate gives 1 mole of lead ion.

Concentration of lead ion in the solution = 1\times 0.010 M= 0.010 M

Pb(Cl)_2(aq)\rightleftharpoons  Pb^{2+}(aq)+2Cl^{-}(aq0

Concentration of chloride ions = [Cl^-]

The value of K_{sp} for [tex]PbCl_2= 1.6\times 10^{-5}

K_{sp}=[Pb^{2+}][Cl^{-}]^2

1.6\times 10^{-5}=0.010 M\times [Cl^{-}]^2

[Cl^-]=0.04 M

0.04 M is the lowest concentration of chloride ions that would be needed to begin precipitation.

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4 years ago
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