The reaction is,
H2S + I2 --------------> 2 HI +S
Molar weight of H2S = 34 g per mol
Molar weight of HI =128 g per mol
Molar weight of I2 =254 g per mol
Moles of H2S in 49.2 g = 49.2 /34 mol = 1.447 mol
So according to stoichiometry of the reaction, number of I2 mols needed
= 1.447 mol
The mass of I2 needed = 1.447 mol x 254 g
Answer : The O-O bond in
will be longer than the O-O bond in
.
Explanation :
In the
, the two oxygen atoms are bonded by the single bond and in
, the two oxygen atoms are bonded by the double bond.
As we know, the bond strength of double bond is greater than the single bond.
And the relation between the bond strength and bond length is,

That means the higher the strength, the shorter will be the bond length.
Hence, the bond length of single bond will be longer than the double bond.
The structure of given molecule is shown below.
The answer to this question is 2 and 3
The theoretical yield is the reaction yield that measures the product of the reaction from the conversion of the limiting reagent. The theoretical yield is 160 gm.
<h3>What is mass?</h3>
Mass or the theoretical yield is the result of the multiplication of mole and the molar mass of the compound.
The reaction between hydrogen and oxygen is shown as,

Moles of water is calculated as:

The theoretical yield of water is calculated as:

Therefore, option D. 160 gm is the theoretical yield of water.
Learn more about theoretical yield here:
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