Answer:
Cos θ = √7/3
Step-by-step explanation:
From the question given above, the following data were obtained:
Sine θ = √2 / 3
Cos θ =?
Recall
Sine θ = Opposite / Hypothenus
Sine θ = √2 / 3
Thus,
Opposite = √2
Hypothenus = 3
Next, we shall determine the Adjacent. This can be obtained as follow:
Opposite = √2
Hypothenus = 3
Adjacent =?
Hypo² = Adj² + Opp²
3² = Adj² + (√2)²
9 = Adj² + 2
Collect like terms
9 – 2 = Adj²
7 = Adj²
Take the square root of both side
Adjacent = √7
Finally, we shall determine the value Cos θ. This can be obtained as follow:
Adjacent = √7
Hypothenus = 3
Cos θ =?
Cos θ = Adjacent / Hypothenus
Cos θ = √7/3
Answer:
yah why
Step-by-step explanation:
Answer:
![1. \quad\dfrac{1}{k^{\frac{2}{3}}}\\\\2. \quad\sqrt[7]{x^5}\\\\3. \quad\dfrac{1}{\sqrt[5]{y^2}}](https://tex.z-dn.net/?f=1.%20%5Cquad%5Cdfrac%7B1%7D%7Bk%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%5C%5C%5C%5C2.%20%5Cquad%5Csqrt%5B7%5D%7Bx%5E5%7D%5C%5C%5C%5C3.%20%5Cquad%5Cdfrac%7B1%7D%7B%5Csqrt%5B5%5D%7By%5E2%7D%7D)
Step-by-step explanation:
The applicable rule is ...
![x^{\frac{m}{n}}=\sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%5Em%7D)
It works both ways, going from radicals to frational exponents and vice versa.
The particular power or root involved can be in either the numerator or the denominator. The transformation applies to the portion of the expression that is the power or root.
