Answer:
(a) 0.16
(b) 1
Explanation:
Let Probability that ticks in the Midwest carried Lyme disease, P(L) = 0.16
Probability that ticks in the Midwest carried HGE disease, P(H) = 0.10
Probability that ticks in the Midwest carried either Lyme disease or HGE disease, P(
) = 0.10
(a) Probability that a tick carries both Lyme disease (L) and HE (H) is given by
P(L
H);
As we know that P(A
B) = P(A) + P(B) - P(A
B)
So, in our question;
P(L
H) = P(L) + P(H) - P(L
H)
0.10 = 0.16 + 0.10 - P(L
H)
P(L
H) = 0.16 + 0.10 - 0.10 = 0.16
Therefore, the probability that a tick carries both Lyme disease (L) and HE (H) is 0.16 or 16% .
(b) <em>Conditional Probability P(A/B) is given by</em> =
So, the conditional probability that a tick has HE given that it has Lyme disease is given by = P(H/L)
P(H/L) =
=
= 1 .
Answer:
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Answer: Option 'C' is correct.
Explanation:
Radioactive forcing increases means the earth will get more energy from sunlight than it radiates to space.
It eventually leads to warming.
So, average temperature would increase in that particular area.
Hence, Option 'C' is correct.
Metaphase, I remember this because "meta" sounds like middle.