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3 years ago

help please: A 15 foot long section beam weighs 3,520 pounds. What is the weight of a 3 foot long section of the beam?

Mathematics

1 answer:

yuradex [85]3 years ago

5 0

Answer:

704 pound's

Step-by-step explanation:

What I did was divided 15 by the 3 and then I got 5 which I divided 3520 pound's by 5 which equals 704 pounds. Hope this helps.

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The mpg (miles per gallon for a certain compact car is normally distributed with a mean of 31 and a standard deviation of 0.8. w

lesantik [10]

For this Q:

mean=31
st.dev.=0.8
x=32

Calculate z-score:
z=(x-m)/s = (32-31)/0.8=1.25

This z-score value corresponding to the probability of 0.8944

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3 years ago

Solve for b:19-b=31

mart [117]

Answer:

-12

Step-by-step explanation:

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2 years ago

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Which number is equal to 15 a)0.015 b)1.5 c)150/100 d)3/20

myrzilka [38]

Answer:

Step-by-step explanation:

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3 years ago

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ElenaW [278]

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3 years ago

Calculate the average rate of change of f(x) = x2 - 1 x - 4 for 2 ≤ x ≤ 6.

hoa [83]

Answer:

Hence, the average rate of change is:

$\dfrac{97}{12}$

Step-by-step explanation:

We are asked to calculate the average value of the function:

$f(x)=x^2-\dfrac{1}{x}-4$ in 2 ≤ x ≤ 6

The average rate of change of the function f(x) in the interval 2 ≤ x ≤ 6 is given as:

$\dfrac{f(6)-f(2)}{6-2}\\\\=\dfrac{f(6)-f(2)}{4}$

Now,

$f(6)=36-\dfrac{1}{6}-4\\\\f(6)=32-\dfrac{1}{6}\\\\f(6)=\dfrac{191}{6}$

$f(2)=4-\dfrac{1}{2}-4\\\\\\f(2)=-\dfrac{1}{2}$

Hence, the average rate of change is:

$\dfrac{\dfrac{191}{6}-\dfrac{-1}{2}}{4}\\\\=\dfrac{194}{6\times 4}\\\\=\dfrac{97}{12}$

Hence, the average rate of change is:

$\dfrac{97}{12}$

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3 years ago

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