Answer:
n = 98, that is, she scored at the 98th percentile.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
She scored 38, so 
Test scores are normally distributed with a mean of 25 and a standard deviation of 6.4.
This means that 
Find the percentile:
We have to find the pvalue of Z. So



has a pvalue of 0.98(rounding to two decimal places).
So n = 98, that is, she scored at the 98th percentile.
If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up (+1).
If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down (no change).
Answer:
No solutions
Step-by-step explanation:
Answer:
$9,960
Step-by-step explanation:
249000 x 0.4 = 9960
D
Divide the whole thing by 2
2(X^2+8x-5)
X^2+8x. =5
Half of 8 is 4 sq it so you add 16
X^2+8x+16= 5+16
(X+4)^2=21