So car A travels Distance = 60 km/hr*(1+x)
Car B travels Distance = 75 km/hr(x)
Where x is the time in hours.
Those two equations are equal when on overtakes the other
so:
60 +60x = 75x
60=15x
x=4, but my expression is written to count from when car B commenced travel. So total time is 5 hours from the car A setting off.
Answer:
I think it might be A if not then its be
Step-by-step explanation:
sorry if its not right
The x - intercept of 5x - 3y = 15 is (3, 0)
The y -intercept of 5x - 3y = 15 is (0, -5)
<h3><u>Solution:</u></h3>
Given equation is 5x - 3y = 15
<em><u>To find: x - intercept and y -intercept</u></em>
The x intercept is the point where the line crosses the x axis. At this point y = 0
The y intercept is the point where the line crosses the y axis. At this point x = 0.
<em><u>Finding x - intercept:</u></em>
To find the x intercept using the equation of the line, plug in 0 for the y variable and solve for x
So put y = 0 in given equation
5x - 3(0) = 15
5x = 15
x = 3
So the x - intercept is (3, 0)
<em><u>Finding y - intercept:</u></em>
To find the y intercept using the equation of the line, plug in 0 for the x variable and solve for y
So put x = 0 in given equation
5(0) - 3y = 15
-3y = 15
y = -5
So the y - intercept is (0, -5)
1. A pair of supplementary angles: ∠IJH and ∠HJG, ∠IJH and ∠HJG
2. A pair of complementary angles: ∠JGK and ∠KGC, ∠FGE and ∠EGD
3. A pair of vertical angles: ∠AKB and ∠KJG , ∠IJH and ∠KJG
Solution:
<em>Two angles are said to be supplementary when they add up to 180°.</em>
We know that,
Sum of the adjacent angles in a straight line = 180°
∠IJK + ∠KJG = 180°
Therefore ∠IJK and ∠KJG are supplementary angles.
∠IJH + ∠HJG = 180°
Therefore ∠IJH and ∠HJG are supplementary angles.
<em>Two angles are said to be complementary when they add up to 90°.</em>
Given ∠CGD = 90°, ∠CGJ = 90°
∠JGK + ∠KGC = ∠CGJ
∠JGK + ∠KGC = 90°
Therefore ∠JGK and ∠KGC are complementary angles.
∠FGE + ∠EGD = 90°
Therefore ∠FGE and ∠EGD are complementary angles.
<em>If two lines are intersecting, then the angles opposite to vertical point are vertical angles and they are equal.</em>
∠AKB = ∠KJG (vertically opposite)
∠IJH = ∠KJG (vertically opposite)
<u>Equivalent Fractions 1/2</u>
2/4
3/6
4/8
5/10
6/12
<u>Equivalent Fractions 1/4</u>
2/8
3/12
4/16
5/20
6/24
<u>Equivalent Fractions 1/8</u>
2/16
3/24
4/32
5/40
6/48
<u>Equivalent Fractions 1/3</u>
2/6
3/9
4/12
5/15
6/18
<u>Equivalent Fractions 1/6</u>
2/12
3/18
4/24
5/30
6/36
