From the information given;
1 bag of concrete = 1000 in^3
2 bags at home = 1000*2 = 2000 in^3
The available space has a volume of;
Volume = (5*12)*10*10 (Note: 1 ft = 12 inches)
Volume = 60*10*10 = 6000 in^3
The remaining volume = Available space - occupied space = 6000 - 2000 = 4000 in^2
1 bag = 1000 in^3
x bags = 4000 in^2
Then,
x = 1*4000/1000 = 4 bags.
This means 4 more bags of concrete will be required to fully fill the space.
Move everything around. d+1.6=9.7. d=8.1.
The answer to this would be FF -> T
Answer:
$4
Step-by-step explanation:
if its $2 per packet and he is buying 3 do 2x3 which is 6 then 10-6 which is $4
Operación: (+6)-(3). Piso Final: +3
Inicial: +8 Operación: (+8)+(+1) Piso final: +9
Inicial: +10 Operación: (+10)-(4) Piso final: +6