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GenaCL600 [577]
3 years ago
13

Kate has 787 pennies in her piggy bank. She earns 292 pennies by

Mathematics
2 answers:
ddd [48]3 years ago
7 0

Answer: 1079. Rounded 1000

Step-by-step explanation:

ivolga24 [154]3 years ago
3 0

the total number of pennies Kate's have can be known by adding all the pennies.

=787 + 292

=1079

the nearest round off of the pennies is 1000

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DerKrebs [107]
I hope my ans is correct!! used some algebra here but yea i hope its still comprehensible!

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3 years ago
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Find the missing of the triangle Round to the nearest tenth
inessss [21]

Answer:

Step-by-step explanation:

This is a 30°-60°-90° triangle, so its sides are in the ratio 1:√3:2

The side opposite the 90° angle is 11, so the side opposite the 30° angle is 11/2 = 5.5

x is opposite the 60° angle, so its length is 5.5√3 ≅ 9.5 units

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3 years ago
Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even. what kind of proof did you
scoray [572]
Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n

Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
6 0
3 years ago
4. For f(x) = 1/x-5
ioda

Answer:

  • g(x) = x^2 +2
  • f(g(x)) = 1/(x^2 -3)

Step-by-step explanation:

A. g(x) is given:

  g(x) = x^2 +2

__

B. f(g(x)) = f(x^2 +2) = 1/((x^2 +2) -5) . . . . substitute for g(x) and simplify

  f(g(x)) = 1/(x^2 -3)

3 0
3 years ago
Find an equation of the tangent to the curve x =5+lnt, y=t2+5 at the point (5,6) by both eliminating the parameter and without e
svet-max [94.6K]

ANSWER

y = 2x -4

EXPLANATION

Part a)

Eliminating the parameter:

The parametric equation is

x = 5 +  ln(t)

y =  {t}^{2}  + 5

From the first equation we make t the subject to get;

x - 5 =  ln(t)

t =  {e}^{x - 5}

We put it into the second equation.

y =  { ({e}^{x - 5}) }^{2}  + 5

y =  { ({e}^{2(x - 5)}) }  + 5

We differentiate to get;

\frac{dy}{dx}  = 2 {e}^{2(x - 5)}

At x=5,

\frac{dy}{dx}  = 2 {e}^{2(5 - 5)}

\frac{dy}{dx}  = 2 {e}^{0}  = 2

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

y-y_1=m(x-x_1)

y - 6 = 2(x - 5)

y = 2x - 10 + 6

y = 2x -4

Without eliminating the parameter,

\frac{dy}{dx}  =  \frac{ \frac{dy}{dt} }{ \frac{dx}{dt} }

\frac{dy}{dx}  =  \frac{ 2t}{  \frac{1}{t} }

\frac{dy}{dx}  =  2 {t}^{2}

At x=5,

5 = 5 +  ln(t)

ln(t)  = 0

t =  {e}^{0}  = 1

This implies that,

\frac{dy}{dx}  =  2 {(1)}^{2}  = 2

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

y-y_1=m(x-x_1)

y - 6 = 2(x - 5) =

y = 2x -4

5 0
3 years ago
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