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Elena-2011 [213]
3 years ago
6

A scale of the Golden Gate Bridge in San Francisco Bay has

Mathematics
1 answer:
lora16 [44]3 years ago
3 0

Answer:

2520ft

Step-by-step explanation:

Calculation for what is the scale of the model?

Let x will be the span length

Hence,

x= 4200 feet long/20 inches long

x=210

Thus:

1 inch = 210 ft

1 ft = 2520

=2520ft

Therefore the scale of the model will be 2520ft

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What is the solution to this inequality x-7<1
Nina [5.8K]
X−7<1

Add 7 to both sides.

x−7+7<1+7

x<8

To plot this on a number line, put a circle around 8 and a line going to the left with an arrow at the end.
8 0
4 years ago
Read 2 more answers
How do i factor a trinomial
Lilit [14]

Answer:

See below

Step-by-step explanation:

Factoring a trinomial of the form ax^2 + bx + c.

I think this is best  understood by studying some examples.

<u>Examples</u>:-

Trinomials where a = 1:-

Factor x^2 + 3x + 2     (Its not usually written as 1x^2).

We need 2 numbers whose product = the last term (2) and whose sum = 3 ( the coefficient of x).

They are 1 and 2.  The factors are  2 binomials as follows:-

(x + 1)(x + 2)  (answer)


2.    Factor  x^2 - x - 6

We need 2 numbers whose product is -6 and whose sum = -1 ( its -1 because we can write the middle term - x as -1x ).

The 2 numbers are -3 and  2 , so the factors are:-

(x - 3)(x + 2)  (answer)

----------------------------------

Now we come to trinomials  that have a value of a > 1:-

Example 1.

Factor 2x^2 + 5x + 2

We can use the 'ac' method.

First multiply 'a' by 'c'      (  from ax^2 + bx + c):-

2 * 2 = 4.

Now  we need 2 numbers whose product is 4 and whose sum is the coefficient of x, (=  5). These are

4 and 1.

Now we rewrite the 5x in the  trinomial  as 4x + x :-

2x^2 + 5x + 2

= 2x^2 + 4x + x + 2

Next Factor this by grouping:-

= 2x(x + 2) + 1(x + 2)

Note that x + 2 is common so w have the factors:-

(2x + 1)(x + 2)     (answer).


Example 2.

Factor  3x^2 - 10x - 8

3 * -8 = -24

The 2  required numbers  are  -12 and 2  because -12*2 = -24 and -12 + 2 = -10. So we write:-

3x^2 - 12x + 2x - 8

=  3x(x - 4) + 2(x - 4)

=  (3x + 2)(x - 4)    (answer).

Hope this helps.

My advice is Practice as much as you can.


5 0
4 years ago
The perimeter of this shape is 108.5 in. What is the length of side d? <br> ______<br> l_____l in.
sergeinik [125]
The answer is 25.9. To find it add the other sides (21.5 + 32.4 + 28.7 = 82.6) Then take the perimeter (108.5) and subtract (108.5 - 82.6 = 25.9)
5 0
3 years ago
Read 2 more answers
Help please <br><br>need to rewrite the table if you know how write the equation for the table​
andrew11 [14]

Answer:

  • a.  linear: y = 42-2x
  • b.  non-linear: y = x(x +3)/2

Step-by-step explanation:

A function is linear if x-values are evenly spaced (all have the same difference) and y-values are evenly spaced (all have the same difference).

a) x-values have a difference of 6 -3 = 9 -6 = 12 - 9 = 3. y-values have a difference of 30 -36 = 24 -30 = 18 -24 = -6. Both these differences are constant, so the function is <em>linear</em>.

The ratio of y-differences to x-differences is -6/3 = -2, so that is the slope of the line. We can use the point-slope form to discover an equation in slope-intercept form.

Point-slope form of the equation for a line with slope m through point (h, k) can be written as ...

  y = m(x -h) +k

Here, we have m = -2, and the first point is (h, k) = (3, 36). Then our line's equation can be written as ...

  y = -2(x -3) +36

  y = -2x +42 . . . . . . . eliminating parentheses

__

b) The x-values in this table have a constant difference of ...

  3 -1 = 5 -3 = 7 -5 = 2

The y-values have differences of 9 -2 = 7, 20 -9 = 11, 35 -20 = 15. These are not constant, so the relation is <em>non-linear</em>. These first differences have differences of ...

  11 -7 = 15 -11 = 4 . . . . . second differences are constant

When second differences are constant, the relation can be described by a second degree polynomial. We can write some equations to discover what that polynomial is.

Generic form:

  ax² +bx +c = y

Filling in three of the given points, we have three equations in a, b, c:

  a·1² + b·1 +c = 2

  a·3² +b·3 +c = 9

  a·5² +b·5 +c = 20

Subtracting the first equation from the other two eliminates c and gives two equations in a and b:

  a·(9 -1) +b(3 -1) = 9 -2 . . . . . . . . . 8a +2b = 7

  a·(25 -1) + b·(5 -1) = 20 -2 . . . . .  24a +4b = 18

Subtracting twice the first of these equations from the second, we can eliminate b:

  a(24 -2·8) = 18 -2·7

  8a = 4

  a = 1/2 . . . . . divide by 8

Substituting this into the first of the equations in a and b, we get:

  8·(1/2) +2b = 7

  2b = 3 . . . . . subtract 4

  b = 3/2 . . . . divide by 2

Substituting for a and b in the first of our original equations, we find ...

  (1/2)·1 + (3/2)·(1) +c = 2

  2 +c = 2 . . . simplify

  c = 0 . . . . . . subtract 2

So, the table in part b can be described by the quadratic equation ...

  y = (1/2)x² + (3/2)x

5 0
4 years ago
Consider a triangle ABC like the one below. Suppose that =A110°, =b25, and =c4. (The figure is not drawn to scale.) Solve the tr
tamaranim1 [39]

Side a, angle B and angle C of triangle ABC are 26.6 units, 61.9 degrees and 8.1 degrees respectively.

<h3>What is the value of the missing angles and side?</h3>

Given that;

  • Angle A = 110°
  • Side b = 25
  • side c = 4
  • side a = ?
  • Angle B = ?
  • Angle C = ?

First we determine the length of side a

a = \sqrt{b^2-c^2-2bc*cos(A)}

We substitute our values into the above equationa = \sqrt{25^2-4^2-(2*25*4*cos(110)}\\\\a = 26.6

Side a has a length of 26.6 units.

B = cos^{-1}(\frac{a^2+c^2-b^2}{2ac}) \\\\B = cos^{-1}(\frac{26.63464^2+4^2-25^2}{2*26.63464*4}) \\\\B = 61.9

Angle B is 61.9 degrees.

C = cos^{-1}(\frac{a^2+b^2-c^2}{2ab} )\\\\C = cos^{-1}(\frac{26.63464^2+25^2-4^2}{2*26.63464*25} )\\\\C =8.1

Angle C is 8.1 degrees.

Therefore, side a, angle b and angle c of the triangle ABC are 26.6 units, 61.9 degrees and 8.1 degrees respectively.

Learn more about triangles here: brainly.com/question/14882091

#SPJ1

5 0
2 years ago
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