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Dmitrij [34]
3 years ago
12

Which polynomial represents the sum below?

Mathematics
1 answer:
marin [14]3 years ago
7 0

Answer:

C

Step-by-step explanation:

(4x^2+1)+(4x^2+x+2)= \\\\(4x^2+4x^2)+x+(1+2)= \\\\8x^2+x+3

Hope this helps!

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Unit rate of 15 pounds in 6 weeks<br><br> Please help me!!! Will mark as brainiest!
erastova [34]
The unit rate is 2.5 pounds a week.
15/6 = 2.5
I hope this helps.
3 0
3 years ago
Read 2 more answers
6 children and 2 adults are going to the circus, children tickets are on sale, half the price of adult tickets totaling $54. How
inna [77]

Answer:

Price of 1 child ticket is $5.4

Price of 1 adult ticket is $10.8

Step-by-step explanation:

Given:-

6 children and 2 adults are going for circus.

Children ticket is half the price of adult ticket.

Total ticketing cost =$54

To find:-

Cost of 1 child ticket=?

Cost of 1 Adult ticket=?

Solution:-

Let price of 1 child ticket be x and price of 1 adult ticket be y,

therefore from the given data we get 2 equations,

6x+2y=54                          -----------------------------------(1)

x=\frac{1}{2} y                    --------------------------------(2)

Now, substituting the value of x from equation 2 in equation 1,

6x+2y=54

6(\frac{1}{2} y)+2y=54

\frac{6}{2}y+2y=54

3y+2y=54

5y=54

\therefore y=\frac{54}{5}

\therefore y =10.8          ------------------------(3)

Now, substituting the value of y from equation 3 in equation 2,

x=\frac{1}{2} y

\therefore x=\frac{1}{2} \times 10.8       ------------(from equation 3)

\therefore x=\frac{10.8}{2}

\therefore x=5.4              ----------------------(4)

As, x is price of 1 child ticket and y is price of 1 adult ticket,

Therefore price of 1 child ticket is $5.4 and price of 1 adult ticket is $10.8

7 0
3 years ago
What is wrong with the following proof? Clearly we know that 1 does not equal 2. What rule of algebra did we break that makes th
Gnoma [55]

An attempt to divide by zero gives a contradictory result

A rule of algebra broken is <u>dividing by zero</u> (leading to a contradiction) and stating a finite result

Reason:

The given calculation is presented as follows;

1. a > 0, b > 0 given

2. a = b given

3. a·b = b²

4. a·b - a² = b² - a²

5. a·(b - a) = (b + a)·(b - a)

6. a = b + a

7. 0 = b

8. b = 2·b

9. 1 = 2

From line 4, the result are;

4. a·b - a² = b² - a² = 0

5. a·(b - a) = (b + a)·(b - a) = 0

On line 6, both sides where divided by (b - a) = 0, which should given an infinite result

Therefore, one rule of algebra broken is dividing by zero to get a finite result

In line 7, we have;

7. 0 = b

From 6. a = b + a, and a = b, we have;

8. b = 2·b

Therefore, line 9 should be;

9. 0 = 2·0; 0 = 0, given that we have;

1 × 0 = 0

2 × 0 = 0

∴ 1 × 0 = 2 × 0

However

  • 1 ≠ 2

In line 9., by dividing by b = 0, again, we have;

  • 9. 1 = 2 (a contradiction)

Therefore, one rule of algebra that is broken is <u>dividing by zero</u> and having a finite result

Learn more about the rules of algebra here:

brainly.com/question/11388301

5 0
2 years ago
A compound proposition that is always ___________ is called a contradiction. A. True B. False
alexandr1967 [171]

Answer:

<em>A compound proposition that is always false is called a contradiction</em>

Step-by-step explanation:

3 0
2 years ago
3/5 of a number decreased by one is 23. What is the number?
garri49 [273]
You can set up an equation based off of the information given:

x represents the unknown number

3/5x - 1 = 23

add 1 to both sides to isolate the 3/5x

3/5x = 24

divide both sides by 3/5 to solve for x

x = 120/3

120/3 can be simplified into 40

Final answer: x = 40
5 0
3 years ago
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