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3 years ago

Find the missing coordinate to complete the ordered pair.

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

8 0

(9,-4) you have to plugin 9 to the equation in the form of x. Then you add 5 and that would be your y value

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Find in the table for any missing values. Please help!!!

Oxana [17]

Answer:

1:3

2:6

3:9

5:15

Step-by-step explanation:

Ask yourself: What times 3 equals my number?

As you can see 1x3=3 then 2x3=6, 3x3=9, and lastly 5x3=15

This is how you solve the chart.

8 0

3 years ago

In the formula, l = a + (n - 1)d make d as the subject. Find d when l = 10, a = 2, n = 5.

coldgirl [10]

<h3>Given:-</h3>

I = a + (n - 1)d [Given formula]

Find d when I = 10, a = 2, n = 5

<h2>Solution:-</h2>

I = a + (n - 1)d [Given]

Putting the value of I = 10, a = 2, n = 5 we get,

10 = 2 + (5 - 1)d

10 = 2 + 4d

10 - 2 = 4d

8 = 4d

d = $\frac{8}{4}$

d = 2

<h3>Value of d is 2. [Answer]</h3>

6 0

3 years ago

Jason wants to eam money by raking leaves. He buys a rake that costs $30.00. He plans to charge $8.00 for each lawn that he rake

alukav5142 [94]

Answer:

$90 profit

Step-by-step explanation:

4 0

3 years ago

How to solve (2x-3)(3x+3)=36

mote1985 [20]

Use the distributive property to multiply the two sets of parentheses. You should have learned this in Algebra 1.

7 0

3 years ago

Read 2 more answers

Help! Exponential Equation WITHOUT CALCULATOR

ale4655 [162]

$
1.
(2^{x} -2^{-x})^{2} = 4^{2} \\ \\2^{2x}-2*2^{x}*2^{-x} + 2^{-2x} =4^{2} \\ \\2^{2x}-2*2^{x-x} + 2^{-2x} =4^{2} \\ \\ 2^{2x}+ 2^{-2x} - 2=16 \\ \\ 2^{2x}+ 2^{-2x} = 18

\\ \\ 2.( 2^{x})^{3} - (2^{-x}^) ^{3}= (2^{x} -2^{-x})(2^{2x}+2^{x}*2^{-x}+2^{-2x})
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})(2^{2x}+2^{-2x}+2^{x}*2^{-x})
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})(2^{2x}+2^{-2x}+1)
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})((2^{2x}+2^{-2x})+1)
$

$\\ \\ ( 2^{x})^{3} - (2^{-x})^{3} =(4)((18)+1)= 76
\\ \\ 2^{3x}-2^{-3x} =76
$

4 0

3 years ago