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Lorico [155]
3 years ago
10

A cat pushes a ball from a 7.00 m high window, giving it a horizontal velocity of 0.20 m/s. how far from the base of the buildin

g does the ball land? (assume no air resistance and that ay= g = 9.81 m/s2.)
Physics
1 answer:
m_a_m_a [10]3 years ago
4 0
Formulas are:
h = g t² / 2
x = v x * t
7 m = 9.81 m/s² * t² / 2
t² = 14 : 9.81
t² = 1.427
t = √1.427 = 1.19 s
x = 0.2 m/s * 1.19 s
x = 0.24 m
Answer: The ball lands 0.24 m from the base of the building.
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Which of the following is/are true? Electromagnetic waves are created by accelerating charges. Electromagnetic waves are transve
Vikki [24]

Answer:

All of the above are true.

Explanation:

(a). true  

whenever  charge particle  move back and froth from its mean position then it will produce oscillating electric and magnetic fields, . so an em wave can be obtain by accelerating charge

(b). true

the electric field and the magnetic field have vibrations in the perpendicular direction along  the motion of the wave  so electromagnetic wave is a transverse wave. therefore, the EM wave is a Transverse wave

(c) true .

The Electromagnetic wave consists of the two mutually perpendicular electric and magnetic fields  and also both fields are  perpendicular to the direction of propagation of the wave.

(d) true .

An electromagnetic wave  carry  energy through  vacuum with a speed   of 3 \times 10^8 m/s  

   so , all of the above are true.

4 0
3 years ago
A 0.40 kg mass hangs on a spring with a spring constant of 12 N/m. The system oscillated with a constant amplitude of 12 cm. Wha
Vaselesa [24]

Answer:

The maximum acceleration of the system is 359.970 centimeters per square second.

Explanation:

The motion of the mass-spring system is represented by the following formula:

x(t) = A\cdot \cos (\omega \cdot t + \phi)

Where:

x(t) - Position of the mass with respect to the equilibrium position, measured in centimeters.

A - Amplitude of the mass-spring system, measured in centimeters.

\omega - Angular frequency, measured in radians per second.

t - Time, measured in seconds.

\phi - Phase, measured in radians.

The acceleration experimented by the mass is obtained by deriving the position equation twice:

a (t) = -\omega^{2}\cdot A \cdot \cos (\omega\cdot t + \phi)

Where the maximum acceleration of the system is represented by \omega^{2}\cdot A.

The natural frequency of the mass-spring system is:

\omega = \sqrt{\frac{k}{m} }

Where:

k - Spring constant, measured in newtons per meter.

m - Mass, measured in kilograms.

If k = 12\,\frac{N}{m} and m = 0.40\,kg, the natural frequency is:

\omega = \sqrt{\frac{12\,\frac{N}{m} }{0.40\,kg} }

\omega \approx 5.477\,\frac{rad}{s}

Lastly, the maximum acceleration of the system is:

a_{max} = \left(5.477\,\frac{rad}{s})^{2}\cdot (12\,cm)

a_{max} = 359.970\,\frac{cm}{s^{2}}

The maximum acceleration of the system is 359.970 centimeters per square second.

7 0
3 years ago
Which of the following cannot be determined by analyzing the periodic table?
dybincka [34]

Your answer is C) The year the element was discovered :)

4 0
3 years ago
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Estimate the volume of a human heart (in mL) using the following measurements/assumptions:_______.
uysha [10]

Answer:

Explanation:

radius of aorta = 1.5 cm

cross sectional area = π r²

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= 7.065 x 11.2

= 79.128 cm³

heart beat per second = 67 / 60

= 1.116666

If V be the volume of heart

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3 years ago
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This is something I have no idea
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