There is no definite way to answer this question without further, more detailed information. I am truly sorry I am unable to answer this with the information provided.
"y>-2x+2 and y>-2x+5" are illustrated graphically by 2 straight dashed lines with slope -2. The lines are parallel because their slopes (-2) are the same. One line has y intercept 2 and the other has y intercept 5. The latter is above the former. Since both inequality signs are " > " we must shade the area ABOVE each of the 2 lines. The solution set is the area of the graph that has been shaded twice, once for y>-2x+2 and again for y>-2x+5. It's y>-2x+5 that has been shaded twice; this area is immediately above the line y>-2x+5.
A(-4, -1)
B(-3, -3)
C(0, 2)
Yo sup??
The coordinates of vertices in 1st quadrant are
(2,5),(2,2) and (5,5)
Hope this helps
The answer would be D I and II only
My work:
The only answer that has both statement I and statement II as true is D<span>, but if you have time and want to be absolutely thorough, you can also check to see if statement III is true </span>
