For most genes on the human X chromosome, 100% of XY males with mutant allele on the X chromosome will express the mutant phenotype.
50 % of human sperm cells that carry an X chromosome. There is 50 % chances that daughter of any male will not carry the gene and can't pass it on and 50 % chance that sons do not have the gene and it will be healthy. 50% chance that son have inherited the gene and express the trait or disorder.
If a Egg is fertilizes by sperm with X chromosome then zygote will be a female ' XX'. If the Egg is fertilizes by sperm with Y chromosome , then zygote will be male 'XY'.
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Answer:
By monitoring changes in the population of a specific indicator species, scientists may draw conclusions about changes in a specific pollutant's levels. In addition, this method of pollution measurement demonstrates the impact of pollution on vulnerable species.
Explanation:
C. Deoxyribose sugar because the phospahte group, the nitrogen base, and ribose sugar is needed for ATP.
About the question:
I failed to find the complete question with the Punnett square, so in the answer and explanation I will propose five options for crosses between dogs with different genotypes, and for each option, I will remark the percent of the offspring that is expected to have wirehair. You just need to look for the option that matches your Punnett Square.
Answer:
- Option 1: HH x HH ----> 100% of the progeny is wire-haired, HH
- Option 2: HH x Hh---> 100% of the progeny is wire-haired, HH + Hh
- Option 3: Hh x Hh --->75% of the progeny is wire-haired, 25% HH + 75% Hh
- Option 4: Hh x hh ---> 50% of the progeny is wire-haired, Hh
- Option 5: hh x hh ----> 0% of the progeny is wire-haired
Explanation:
You will find the complete explanation in the attached files due to technical problems
