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Viktor [21]
3 years ago
8

PLS HELP ME ASAP FOR 12 and 13!!! (SHOW WORK FOR BOTH!!!) + LOTS KF POINTS!!

Mathematics
1 answer:
pychu [463]3 years ago
8 0

12.
Distribute the negative
2x - 5 - 9y + 8 + 16y
Simplify
2x + 7y + 3

13.
Square is 4 sides, all sides are equal
4 ( 4x + 3)
16x + 12

Please mark Brainliest if it helped.


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If ΔEFG ~ ΔLMN with a ratio of 2:1, which of the following is true?
strojnjashka [21]

Answer:

  segment EF over segment LM equals segment FG over segment MN

Step-by-step explanation:

The triangles are similar, not congruent, so any answer choice with the word "congruent" can be ignored.

The sequence of letters in the triangle name tells you the corresponding segments:

  • EF corresponds to LM
  • EG corresponds to LN
  • FG corresponds to MN

Corresponding segments have the same ratio, so ...

  EF/LM = FG/MN . . . . . . matches the first answer choice

  EF/LM = EG/LN . . . . does not match the 3rd answer choice

7 0
3 years ago
PLEASE I REALLY NEED HELP!
vagabundo [1.1K]

Answer:

\frac{3}{28}

Step-by-step explanation:

Probability (P) is calculated as

P = \frac{requiredoutcome}{count}

The first required outcome is a red sweet from a total of 3 + 5 = 8

P( red) = \frac{3}{8}

There are now 2 red left and a count of 7, since 1 has been eaten, thus

P( second red ) = \frac{2}{7}

P( red and red ) = \frac{3}{8}  × \frac{2}{7} = \frac{6}{56} = \frac{3}{28}

6 0
3 years ago
Can someone help me ): i think you should
Dimas [21]

Answer:

54+90+120+150+54= 468

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5 0
3 years ago
Read 2 more answers
An urn contains 2 red marbles and 3 blue marbles. 1. One person takes two marbles at random from the urn and does not replace th
Ghella [55]

Answer:

A) The best way to picture this problem is with a probability tree, with two steps.

The first branch, the person can choose red or blue, being 2 out of five (2/5) the chances of picking a red marble and 3 out of 5 of picking a blue one.

The probabilities of the second pick depends on the first pick, because it only can choose of what it is left in the urn.

If the first pick was red marble, the probabilities of picking a red marble are 1 out of 4 (what is left of red marble out of the total marble left int the urn) and 3 out of 4 for the blue marble.

If the first pick was the blue marble, there is 2/4 of chances of picking red and 2/4 of picking blue.

B) So a person can have a red marble and a blue marble in two ways:

1) Picking the red first and the blue last

2) Picking the blue first and the red last

C) P(R&B) = 3/5 = 60%

Step-by-step explanation:

C) P(R&B) = P(RB) + P(BR) = (2/5)*(3/4) + (3/5)*(2/4) = 3/10 + 3/10 = 3/5

3 0
3 years ago
Solve for x and explain how you got your answer <br> 3x + 4 = 16
12345 [234]

Answer:

X = 4

Step-by-step explanation:

3x=16-4

3x= 12

X=12/3

X= 4

5 0
3 years ago
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