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ValentinkaMS [17]
3 years ago
6

A solid sphere, solid cylinder, and a hollow pipe all have equal masses and radii and are of uniform density. If the three are r

eleased simultaneously at the top of an inclined plane and roll without slipping, which one will reach the bottom first? A. solid sphere B. hollow pipe C. solid cylinder D. They all reach the bottom at the same time
Physics
1 answer:
scZoUnD [109]3 years ago
7 0

Answer:

A )  SOLID SPHERE

Explanation:

Moment of inertia of solid sphere = 2/5 M R²

= M K² , K is called radius of gyration

K = √2/5 R

Moment of inertia of solid cylinder = 1/2  M R²

= M K² , K is called radius of gyration

K = 1 /√2  R

Moment of inertia of solid sphere =  M R²

= M K² , K is called radius of gyration

K =  R

For rolling on inclined plane , acceleration  

a = \frac{gsin\theta}{1+\frac{K^2}{R^2} }

Putting the value of K for solid sphere

a for solid sphere

a = g sinθ / ( 1 +2/5)

a = .714 g sinθ

Putting the value of K for solid cylinder

a for solid cylinder

a = g sinθ / ( 1 +1/2)

a = .666 g sinθ

Putting the value of K for hollow pipe

a for hollow pipe

a = g sinθ / ( 1 +1 )

a = . 5 g sinθ

So we see that acceleration a for solid sphere is greatest and a for hollow pipe is the least. Hence solid sphere will reach the bottom earliest and hollow pipe will reach the bottom the latest.

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A diffraction grating is illuminated simultaneously with red light of wavelength 670 nm and light of an unknown wavelength. The
marusya05 [52]

Answer:

dsin∅ = m× λ

so, dsin∅red = 3(670nm)

also, dsin∅? =5λ?

however ,if they overlap then dsin∅red = dsin∅?

3(670nm) /5 =402nm

∴λ = 402nm

Explanation:

4 0
3 years ago
A force of 100N is applied to move an object a horizontal distance of 20m to the right. The work done by this force on the objec
horsena [70]
WORKDONE = FORCE * DISPLACEMENT
W=F*S
HERE, THE FORCE = 100N AND DISTANCE = 20M
WORKDONE = 100*20
WORKDONE=2000
ITS S.I UNIT IS JOULE OR J
SO, 2000J
5 0
3 years ago
3 bulbs are in series and the same 3 bulbs are in parallel with the same battery. Which bulbs will be dimmer?
Marina86 [1]

3 bulbs are in series and if the same 3 bulbs are in parallel with the same battery then the bulbs that are connected in parallel  will be dimmer

<h3>What is power?</h3>

The rate of doing work is known as power. The Si unit of power is the watt.

Power =work/time

The mathematical expression for the electric power is as follows

P = VI  

The same current flows through both bulbs when they are connected in series. A greater voltage drop across the bulb with the higher resistance will result in higher power dissipation and brightness. In the case of the parallel combination, the bulb will be dimmer

Thus, If the same three bulbs are connected in series and parallel with the same battery, the parallelly connected bulbs will be dimmer, therefore the correct option is A

Learn more about power from here

brainly.com/question/3854047

#SPJ1

3 0
2 years ago
B. Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the
goblinko [34]

We have that the instantaneous velocity of the shuttlecock when it hits the ground is

V_{int}=\sqrt{U^2+19.6H}

From the question we are told

Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the

shuttlecock when it hits the ground? Show your work below.

Generally the equation for acceleration  is mathematically given as

a=v \frac{dv}{dx}\\\\\Therefore\\\\\2ah=v^2-u^2

Where

acceleration is still -9.81 m/s2,

Hence,

V^2-U^2=2(-9.81)*-H

Therefore

V_{int}=\sqrt{U^2+19.6H}

For more information on this visit

brainly.com/question/12319416?referrer=searchResults

7 0
2 years ago
A camera takes a properly exposed photo with a 4.0 mm diameter aperture and a shutter speed of 1/1000 s. If the photographer foc
hoa [83]

Answer:

option E

Explanation:

given,

diameter = 4 mm

shutter speed = 1/1000 s

diameter of aperture = ?

shutter speed = 1/250 s

exposure time to the shutter time

E V = log_2(\dfrac{N^2}{t})

N is the diameter of the aperture and t is the time of exposure

now,

log_2(\dfrac{N^2}{t_1})=log_2(\dfrac{N^2}{t_2})

\dfrac{N_1^2}{t_1}=\dfrac{N_2^2}{t_2}

inserting all the values

\dfrac{4^2}{1000}=\dfrac{N_2^2}{250}

      N₂² = 4

      N₂ = 2 mm

hence , the correct answer is option E

4 0
3 years ago
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