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tensa zangetsu [6.8K]
3 years ago
7

Gravitational potential energy is a function of the _____ and the ________ of an object.

Physics
2 answers:
Hunter-Best [27]3 years ago
8 0

Answer:

C. weight, height

bearhunter [10]3 years ago
4 0

The answer is C. Gravitational potential energy is a function of the weight and the height of an object.

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Multi celled organisms have a ______ surface area to volume ratio than single celled organisms.
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A. Larger. It is larger Bc they r all larger than the other
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3 years ago
Scientists believe that the earth's core is made mostly of:
leva [86]

Answer:

magma

Explanation:

4 0
3 years ago
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the gravitational force between two objects is 1600 and what will be the gravitational force between the objects if the distance
Xelga [282]

I believe this is what you have to do:

The force between a mass M and a point mass m is represented by

F = G\frac{Mm}{r^{2} }

So lets compare it to the original force before it doubles, it would just be the exact formula so lets call that F₁

So F₁ = G(Mm/r^2)

Now the distance has doubled so lets account for this in F₂:

F₂ = G(Mm/(2r)^2)

Now square the 2 that gives you four and we can pull that out in front to give

F₂ = \frac{1}{4} G(Mm/r^2)

Now we can replace G(Mm/r^2) with F₁ as that is the value of the force before alterations

now we see that:

F₂ = \frac{1}{4} F₁

So the second force will be 0.25 (1/4) x 1600 or 400 N.



6 0
3 years ago
A weight of 30.0 N is suspended from a spring that has a force constant of 220 N/m. The system is undamped and is subjected to a
Nimfa-mama [501]

Answer:

F_0 = 393 N

Explanation:

As we know that amplitude of forced oscillation is given as

A = \frac{F_0}{ m(\omega^2 - \omega_0^2)}

here we know that natural frequency of the oscillation is given as

\omega_0 = \sqrt{\frac{k}{m}}

here mass of the object is given as

m = \frac{W}{g}

\omega_0 = \sqrt{\frac{220}{\frac{30}{9.81}}}

\omega_0 = 8.48 rad/s

angular frequency of applied force is given as

\omega = 2\pi f

\omega = 2\pi(10.5) = 65.97 rad/s

now we have

0.03 = \frac{F_0}{3.06(65.97^2 - 8.48^2)}

F_0 = 393 N

6 0
3 years ago
A spacecraft is traveling in interplanetary space at a constant velocity. What is the estimated distance traveled by the spacecr
vekshin1

i would say that the correct answer would be cc


3 0
3 years ago
Read 2 more answers
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