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Brilliant_brown [7]
3 years ago
11

A student drops a rock from a bridge to the

Physics
1 answer:
qaws [65]3 years ago
6 0

Answer:

let us use the expression v = ./2gS in both the cases.

a) In the first case g = 9.8 m/s^2 and S = 10.3 m.

So v = 14.21 m/s

b) in the second case, g = 1.64 m/s^2 and S = 4.2 m = 3.71 m/s

00

Explanation:

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3. Consider a locomotive and the rest of a freight train to be a single object. Suppose the locomotive is pulling the train up a
Nonamiya [84]

Answer:

Action - Pulling up the train.

Reaction - Friction on the locomotive

Explanation:

Locomotive is pulling the train upwards ,

Which is the action force applied by the locomotive,

As a reaction locomotive will be pulled by the train which is the reaction of pulling

Now, considering it as a action on locomotive , friction force will act on it as a reaction upwards which will result to move it upwards.

For train action is pulling up by locomotive and reaction will be friction acting on it downwards.

6 0
3 years ago
पुस्तक विक्रेता ने वीपीपी द्वारा आपको पुस्तक भेजी है?? धन्यवाद देते हुए पत्र लिखिए।
Xelga [282]

Answer:

y e s :))))))))))))))))))))))))))))))))

Explanation:

y - dirdf leter of di alfabet

3 0
3 years ago
Which of the following has greater kinetic energy?
vladimir1956 [14]

Answer:

A

Explanation:

6 0
3 years ago
PLS HELP ME WITH THIS
-Dominant- [34]

Answer:

C

Explanation:

C

4 0
3 years ago
A dog runs 300m North and sees the dog catcher and runs 120 m south .Whats the dogs displacement.The same jogger runs 3 miles ar
ozzi

Answer:

<em>1. 180 m</em>

<em>2. 1.5 miles/hour</em>

<em>3. 0 m/s </em>

Explanation:

The complete question is

A dog runs 300 m North and sees the dog catcher and runs 120 m south Whats the dogs displacement.

A jogger runs north for 3.0 miles. If this took 2.0 hours, what is the jogger’s average velocity in miles per hour?

The same jogger runs 3.0 miles on the track, starting and finishing his run after completing exactly 12 laps around the track. What is his average velocity?

1. Displacement is how far the dog moves from the original starting point.

If the dog runs 300 m north, and then 120 m south, then the displacement from the starting point will be

displacement = 300 - 120 = <em>180 m</em>

2. Displacement of the jogger = 3 miles

Time taken by the jogger = 2 hours

velocity of the jogger = ?

Velocity is = displacement/time

velocity = 3/2 = <em>1.5 miles/hour</em>

3. velocity = displacement/time

if the jogger completes exactly 12 laps around the track, then the jogger will return to the starting point. This means that the jogger's displacement from the starting point is 0 miles

Jogger's velocity will therefore be = <em>0 m/s </em>

8 0
3 years ago
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