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2 years ago

The cylinder valve is open and the gas is collected and atmospheric pressure

Physics

1 answer:

jok3333 [9.3K]2 years ago

4 0

Less gas will be collected because some of the gases will escape from the open cylinder valve.

Cylinders used to store carbon dioxide will have thicker walls than those of butane because of higher pressures.

<h3>What are compressed gases?</h3>

Compressed gases are gases which are compressed under high pressure in gas cylinders.

Cylinder valves are used to reduce the pressure of the compressed gases and in the process, some of the gas molecules escape.

Since the cylinder valve is open and the gas is collected at atmospheric pressure, less gas will be collected because some of the gases will escape.

Since, the carbon dioxide not liquefy under pressure compared to butane, the cylinders used to store carbon dioxide will have thicker walls than those of butane.

Learn more about compressed gases at: brainly.com/question/518065

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A squeeze bottle squeezes when pressed. It regains its shape when pressed. It regains its shape when pressure from your hand wit

Vaselesa [24]

Answer:

the bottle would stay in its squashed shape, and it will only regain its shape if u remove the cork

Explanation:

because theres not enough air inside to let the bottle to go back its normal form. Its like when u let the air out of a balloon, theres no air inside to let it stay in its 'big or expanded' form.

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4 years ago

A magnetic field is used to suspend a wire of mass 0.05 kgkg and length 0.16 mm . The wire is carrying a current of 11 AA . What

pochemuha

Answer:

$B=0.27840\ T$

Explanation:

Given:

mass of the wire, $m=0.05\ kg$

length of the wire, $L=0.16\ m$

current in the wire, $I=11\ A$

Now form the Lorentz force we know that every current carrying wire experiences a magnetic force on it due to the magnetic field components perpendicular to it.

Mathematically given as:

$F=I.L\times B$

$m.g=I.L\times B$

here: we nee to balance the gravitational force on the mass.

$B=$ magnetic field

$0.05\times 9.8=11\times 0.16\times B$

$B=0.27840\ T$

This magnetic field must be perpendicular to the direction of current in the wire and the these two directional quantities must lie in a plane normal to the direction of gravity according to the Fleming's left hand rule.

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3 years ago

To lift a load of 100 kg a distance of 1 m an effort of 25 kg must be applied over an inclined plane of length 4 m. What must be

Romashka-Z-Leto [24]

I think the answer is A.

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3 years ago

Read 2 more answers

A car bounces up and down on its springs at 1.0 Hz with only the driver in the car. Now the driver is joined by four friends. Th

romanna [79]

The new frequency of oscillation when the car bounces on its springs is 0.447 Hz

<h3>Frequency of oscillation of spring</h3>

The frequency of oscillation of the spring is given by f = (1/2π)√(k/m) where

k = spring constant and
m = mass on spring

Now since k is constant, and f ∝ 1/√m.

So, we have f₂/f₁ = √(m₁/m₂) where

f₁ = initial frequency of spring = 1.0 Hz,
m₁ = mass of driver,
f₂ = final frequency of spring and
m₂ = mass on spring when driver is joined by 4 friends = 5m₁

So, making f₂ subject of the formula, we have

f₂ = [√(m₁/m₂)]f₁

Substituting the values of the variables into the equation, we have

f₂ = [√(m₁/m₂)]f₁

f₂ = [√(m₁/5m₁)]1.0 Hz

f₂ = [√(1/5)]1.0 Hz

f₂ = 1.0 Hz/√5

f₂ = 1.0 Hz/2.236

f₂ = 0.447 Hz

So, the new frequency of oscillation when the car bounces on its springs is 0.447 Hz

Learn more about frequency of oscillation of spring here:

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2 years ago

What is the relation between centre of gravity and stability

maw [93]

Explanation:

tilting it will raise the height of its center of gravity.

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3 years ago