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3 years ago

How does melting And burning sugar follow the law of conservation of mass

2 answers:

7 0

The Law of Conservation of Mass tells us that matter is neither created nor destroyed during a chemical reaction. ... A burning candle is an example of matter undergoing a chemical reaction and being changed into new substances. Hope this helps ;)

Scorpion4ik [409]3 years ago

4 0

Melting: fisical change.
Same substance, different state of aggregation (liquid, solid, steam)

Burning: chemical change.
Same mass, different substance. Reagents are transformed into products (sugar in carbon and carbon dioxide)

Good luck!
M.

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PLEASE HURRY, I'M BEING TIMED!

spayn [35]

Option D is correct. The speed at which the earth's surface moves because of the earth's rotation will then be equivalent to -10³ km/hr

Speed is a body is defined as the ratio of the distance with respect to the time taken by the body. Mathematically:

Speed = Distance/Time

GIven the following

Distance = 104km/hr

If it is 6:00 p.m. in New York, it is 7:00 a.m. of the next day of the week in Tokyo, this means that the time difference between New York and Tokyo is 11 hours.

Time = -11 hours

Get the required speed

Speed = 104/-11

Speed = -9.454545

Speed = -10km/hr

The speed at which the earth's surface moves because of the earth's rotation will then be equivalent to -10³ km/hr

Learn more here: brainly.com/question/2583051

4 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP

aleksandrvk [35]

Answer:

changing from a solid to a gas without changing into a liquid. :)

6 0

3 years ago

A transverse wave on a long horizontal rope with a

frosja888 [35]

Answer:

2 seconds

Explanation:

The frequency of a wave is related to its wavelength and speed by the equation

$f=\frac{v}{\lambda}$

where

f is the frequency

v is the speed of the wave

$\lambda$ is the wavelength

For the wave in this problem,

v = 2 m/s

$\lambda=8 m$

So the frequency is

$f=\frac{2}{8}=0.25 Hz$

The period of a wave is equal to the reciprocal of the frequency, so for this wave:

$T=\frac{1}{f}=\frac{1}{0.25}=4 s$

This means that the wave takes 4 seconds to complete one full cycle.

Therefore, the time taken for the wave to go from a point with displacement +A to a point with displacement -A is half the period, therefore for this wave:

$t=\frac{T}{2}=\frac{4}{2}=2 s$